AWS BucketPolicy创建失败-策略语法MalformedPolicy无效

问题描述

我正在尝试在yaml中创建以下存储桶策略，但是bucketPolicy无法创建：

Cloudformation错误消息：

Invalid policy Syntax. (Service: Amazon S3; Status Code: 400; Error Code: MalformedPolicy; Request ID: CD4; S3 Extended Request ID: Noxxxx/sXX=; Proxy: null)

需要执行的存储桶策略：

{
    "Version": "2012-10-17","Id": "ig","Statement": [
        {
            "Sid": "LZone","Effect": "Allow","Principal": {
                "AWS": "arn:aws:iam::123:role/l-zone"
            },"Action": [
                "s3:AbortMultipartUpload","s3:ListBucket","s3:PutObject","s3:Getobject","s3:GetobjectVersion","s3:PutObjectAcl"
            ],"Resource": [
                "arn:aws:s3:::bucketname-l/*","arn:aws:s3:::bucketname-l"
            ]
        }
    ]
}

这是上述策略中yaml中的代码（不起作用）：

LBucket:
    Type: AWS::S3::Bucket
    Properties:
      BucketName: !Sub bucketname-l          
LBucketPolicy:
    Type: AWS::S3::BucketPolicy
    Properties:
      Bucket: !Ref LBucket
      PolicyDocument:
        Version: '2012-10-17'
        Statement:
          - Sid: LZone
            Effect: Allow
            Action: 
              - 's3:AbortMultipartUpload'
              - 's3:ListBucket'
              - 's3:PutObject'
              - 's3:Getobject'
              - 's3:GetobjectVersion'
              - 's3:PutObjectAcl'
            Resource:
              Fn::Join:  
              - ""  
              -  
                - "arn:aws:s3:::"  
                -  
                  Ref: "LBucket"  
                - "/*"  
            Principal: "AWS: arn:aws:iam::123:role/l-zone"

有人可以帮我解决我所缺少的内容吗？谢谢

解决方法

政策应为：

const standardDeviation = (arr,usePopulation = false) => {
  const mean = arr.reduce((acc,val) => acc + val,0) / arr.length;
  return Math.sqrt(
    arr.reduce((acc,val) => acc.concat((val - mean) ** 2),[]).reduce((acc,0) /
      (arr.length - (usePopulation ? 0 : 1))
  );
};

console.log('STDEV.S =>',standardDeviation([
    10,2,38,23,21
  ])
);

console.log('STDEV.P =>',21
  ],true)
);