语音识别的Python代码不起作用

问题描述

我经历了与此主题相关的所有类似问题，并尝试了所有方法，但无济于事。

我尝试了以下链接的解决方案： speech recognition python stopped in listen SpeechRecognition producing OSError: No Default Input Device Available Python,Speech Recognition stuck at 'Listening...' speech recognition python code not working等。

import speech_recognition as sr

def get_audio():
    r =  sr.Recognizer()

    with sr.Microphone() as source:
        r.adjust_for_ambient_noise(source,duration=5)
        print("listening... ")
        audio = r.listen(source)
        said = ""

        try:
            said = r.recognize_google(audio)
        except sr.UnkNownValueError:
            print("Google Speech Recognition Could not understand audio")
        except sr.RequestError as e:
            print("Could not request results from Google Speech Recognition service; {0}".format(e))

    return said.lower()         

print(get_audio())

我遇到的错误是：

json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

以下命令被卡在“说某事..”而没有执行任何操作。

 python -m speech_recognition 

我还尝试了以下代码来检查默认音频设备：

import pyaudio
print(pyaudio.pa.get_default_input_device())

输出：

OSError: No Default Input Device Available

我在做什么错了？

解决方法

如上面的评论所述，您似乎没有任何可用的麦克风。

在使用语音识别时，我通常会在听之前询问用户使用哪种设备。

例如，使用这个实现：

# Identify the microphone device to use
def get_microphone_device():
    microphone_list = []
    for index,name in enumerate(sr.Microphone.list_microphone_names()):
        microphone_list.append("Microphone {1} `(device_index={0})`".format(index,name))

    questions = [
    inquirer.List('microphone',message = "What Microphone will you use?",choices = microphone_list,),]
    answers = inquirer.prompt(questions)
    microphone = answers["microphone"]
    microphone = re.search("(?=`)(.*)",microphone).group(0)
    device = re.search("[0-9]",microphone).group()
    return device

然后，要使用设备并获取消息，您可以按照您的操作进行操作，例如：

# Listen to the speaker through the microphone device
def get_speech(device):
    rec = sr.Recognizer()
    with sr.Microphone(device_index=int(device)) as source:
        print("Speak,we are listening:")
        audio = rec.listen(source)
        try:
            text = rec.recognize_google(audio)
            print("You said: \"{}\"".format(text))
        except:
            print("Sorry,we couldn't recognize what you said")
    return text

Here is an example of the full implementation

希望对您有所帮助！