问题描述
我想进行以下替换：用符号＃替换2 <html>
<head>
<script src="p5.min.js"></script>
<script src="C:/full path/src/sketch.js"></script>
</head>
<body>
<main>
</main>
</body
之间的单词$，如果这些单词在2 $之间，则不执行任何操作。
例如，在此文本中：
$$替换将给出：
Currently,we are able to make cross correlations (understand "combine" to have better constraints on cosmological parameters) between weak lensing (WL) and photometric galaxy clustering (GCph). When I say combine,as in the case where I have 2 sets of different measures ($\tau_1,\sigma_1$) and ($\tau_2,\sigma_2$),well,if I consider the Gaussian errors,it is shown quite easily (by Maximum Likelihood Estimation) that the estimator $\sigma_{\hat {\tau}}$ the most representative matches the relation:
$$\dfrac{1}{\sigma_{\hat{\tau}}^{2}}=\dfrac{1}{\sigma_1^2}+\dfrac{1}{\sigma_2^2}$$
我尝试在vim下使用以下命令执行此操作：
Currently,as in the case where I have 2 sets of different measures (#\tau_1,\sigma_1#) and (#\tau_2,\sigma_2#),it is shown quite easily (by Maximum Likelihood Estimation) that the estimator #\sigma_{\hat {\tau}}# the most representative matches the relation:
$$\dfrac{1}{\sigma_{\hat{\tau}}^{2}}=\dfrac{1}{\sigma_1^2}+\dfrac{1}{\sigma_2^2}$$
或
%s/\$[^\$]\(.*\)\$[^\$]/#\1#/g
但这不起作用。我看不到我的错误。
解决方法
您可以在vim中使用此正则表达式替换，使用负向超前和负向超前：
搜索：
:%s/\v\$@<!\$([^$]+)\$\$@!/#\1#/g
替换：
#\1#
说明：
-
%s/：全局替换 -
\v：启动非常魔幻的模式，而不是BRE -
\$@<!：否定性落后，断言我们之前的位置没有$ -
\$：匹配文字$ -
([^$]+)：匹配所有非$字符的1+并将其捕获在＃1组中 -
\$：匹配文字$ -
\$@!：否定前瞻性断言我们前面没有$ -
#\1#：替换为由#包围的＃1组的反向引用