执行童年时，如何获得童年不带任何参数，但是当我删除字符串q中的school时，就会出现NameError

问题描述

当我用q =童年（学校）执行此代码时，我没有童年不带任何参数 但是当我没有执行它时，他们会说没有定义智能 我试图使__init（自我，聪明）来解决它，但只会使情况变得更糟。 所以我想知道这段代码在做错什么吗？

from ex45f import live
class childhood(live):

    def development(self):
        intelligent["low","average","high"]
        if random.choice(intelligent) == low:
            return "You are dumb"
        elif random.choice(intelligent) == average:
            return "You are average"
        else:
            return "You are smart"

        if school == "yes" and intelligent == high:
            return 'You will have an fantastic life'
        elif school == "no" and intelligent == high:
            return "You will have an average life"
        elif school == "maybe" and intelligent == high:
            return "You will have an good life"
        elif school == "yes" and intelligent == average:
            return "You will have an good life"
        elif school == "no" and intelligent == average:
            return "You will have an bad life"
        elif school == "maybe" and intelligent == average:
            return "You will have an average life"
        elif school == "yes" and intelligent == low:
            return "You will have an average life"
        elif school == "no" and intelligent == low:
            return "You will have an horrible life"
        else:
            return "You will have an bad life"
#Zoek op how random choice antwoord bij betrekt
like_school = """Do you like school?
Possible answers: yes,no or maybe
> """
school = input(like_school)
q = childhood(school)
q.development()

解决方法

确保您在类中作为超类传递的是一类，并创建一个构造函数（ init ），并将其作为必需参数，如self和school，并将school分配给self.school并使用它在开发课程中。