问题描述
我刚刚开始编码,我在某个地方遇到了问题,我对JavaScript的了解很少,可能太简单了,我做不到。我正在尝试建立一个水平滚动的网站。我已经使用按钮完成了转换,但是 我想使用导航栏中的链接进行转换 。 当我单击导航链接时,我想要转到其他部分。 我该怎么办?
HTML代码
<div class="navbar">
<a href="" class="logo">
<img src="" alt="" class="logo-img">
</a>
<nav class="nav-list">
<a href="#home" class="nav-link home-btn">HOME</a>
<a href="#about" class="nav-link about-btn">ABOUT</a>
<a href="#portfolio" class="nav-link port-btn">PORTFOLIO</a>
</nav>
</div>
<button class="page-btn left-btn">
<i class="fa fa-arrow-left" aria-hidden="true"></i>
</button>
<button class="page-btn right-btn">
<i class="fa fa-arrow-right" aria-hidden="true"></i>
</button>
<section class="section-1" id="home">
<div class="section-title">
<h1 class="section-1-hd">
SECTION ONE
</h1>
</div>
</section>
<section class="section-2" id="about">
<div class="section-title">
<h1 class="section-2-hd">
SECTION TWO
</h1>
</div>
</section>
<section class="section-3" id="portfolio">
<div class="section-title">
<h1 class="section-3-hd">
SECTION THREE
</h1>
</div>
</section>
Javascript代码
var counter1 = 0;
var counter2 = 1;
const sections = document.querySelectorAll('section');
if(counter1 === 3) {
Array.from(sections).forEach(section =>{
section.style.left = "0"
})
counter1=0;
counter2=1;
}
if(counter1 === -1) {
Array.from(sections).forEach(section =>{
if(section.classList[0] === 'section-3') {
return;
}
section.style.left ='-100vw'
})
counter1=2;
counter2=3;
};
window.addEventListener('wheel',(e) =>{
const deltaY = e.deltaY > 0;
if(deltaY) {
counter1++;
counter2++;
}else {
counter1--;
counter2--;
}
console.log(counter1,counter2);
document.querySelector(`.section-${deltaY ? counter1 : counter2}`).style.left = `${deltaY ? "-100vw" : "0"}`;
});
document.querySelector('.left-btn').addEventListener('click',() => {
counter1--;
counter2--;
document.querySelector(`.section-${counter2}`).style.left = '0';
});
document.querySelector('.right-btn').addEventListener('click',() => {
counter1++;
counter2++;
document.querySelector(`.section-${counter1}`).style.left = '-100vw';
});
我可能写了一个非常糟糕的代码,并为此道歉。
解决方法
首先,我们将所有section元素存储到一个数组中
const sections = document.querySelectorAll('section');
然后,创建一个函数,该函数将导航或将当前滚动x位置设置为下一部分或上一部分。
let index = 0;
function navigate(direction) {
if (direction === 'next') {
index = ++index % sections.length;
}
if (direction === 'prev') {
index = (index > 0) ? --index : index;
}
window.scrollTo(sections[index].getBoundingClientRect().left,0);
}
此函数将当前部分的索引增加1,并通过sections数组的大小将其模量;如果其大于0,则将其减少1。
获取新的部分索引后,我们使用window.scrollTo(x,y)导航到目标部分left
属性。
现在,我们已经完成了javascript,让我们回到HTML。与使用eventListener相比,使用onclick
这样更容易
<button class="page-btn left-btn" onclick="navigate('prev')">
prev
<i class="fa fa-arrow-left" aria-hidden="true"></i>
</button>
<button class="page-btn right-btn" onclick="navigate('next')">
next
<i class="fa fa-arrow-right" aria-hidden="true"></i>
</button>
在onclick
中,我们以{next”或“ prev”作为参数传递navigate
函数
就在那里!
编辑:为此行
index = (index > 0) ? --index : index;
这等效于此
if (index > 0) {
--index;
}
,
如果您愿意使用jquery,我可以从我自己的工具箱中为您提供一个功能。给定一个周围的容器,您的导航项是要滚动到其上的子元素。
包含jquery(有效期至2020/14/09):
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
具有javascript函数进行滚动。像这样,使用.animate(..)
:
/** Will center the scroll-bar of a container onto one of his child elements horizontally.
* @param id_container: id string of the scrollable container.
* @param id_target : id string of the target that is to be centered to.
* Should be a child of above container.
* @param additional_offset: Will be added to the movement computation (pixels).
* @param scroll_time: Number. Time in ms that the transition should take. 200 is a good value. */
function scroll_to(id_container,id_target,additional_offset,scroll_time)
{
//> Preliminaries. -------------------------------------------------
if (additional_offset===undefined) { additional_offset=0; }
if (scroll_time===undefined) { scroll_time=200; }
var cont = $("#"+id_container);
var target = $("#"+id_target);
//< ----------------------------------------------------------------
//> Actual strolling scrolling. ------------------------------------
var site = target.position().left + additional_offset - cont.innerWidth()/2.0 + cont.scrollLeft();
cont.animate({ scrollLeft: site },scroll_time);
//< ----------------------------------------------------------------
}
顺便说一句:整个动画内容实际上只是一点点糖。核心解决方案是在周围的容器scrollLeft
上设置CSS属性。参见例如此处:
https://developer.mozilla.org/en-US/docs/Web/API/Element/scrollLeft