问题描述
以下作品:
QTransaction.transaction.postingText.lower().like("%" + filter.getPostingText().toLowerCase() + "%"))
我正在尝试类似的查询,但是用u替换x:
Expressions.stringTemplate("replace({0},'x','u')",QTransaction.transaction.postingText.lower()).like("%" + filter.getPostingText().toLowerCase() + "%"));
日志显示:
replace(lower(transaction.postingText),'u') like ?5 escape '!'].
The right expression is not a valid expression.
我在做什么错了?
@Bean
@DependsOn("jmsConnectionFactory")
public LocalContainerEntityManagerfactorybean entityManagerFactory() throws Exception {
EclipseLinkJpavendorAdapter vendorAdapter = new EclipseLinkJpavendorAdapter();
vendorAdapter.setGenerateDdl(false);
vendorAdapter.setDatabasePlatform("org.eclipse.persistence.platform.database.PostgresqlPlatform");
vendorAdapter.setShowsql(false);
LocalContainerEntityManagerfactorybean factory = new LocalContainerEntityManagerfactorybean();
factory.setJpavendorAdapter(vendorAdapter);
List<String> packages = new ArrayList<>();
packages.addAll(Arrays.asList(PACKAGES_TO_SCAN_DATA_ENTITIES));
packages.addAll(additionalPackagesToScan);
factory.setPackagesToScan(packages.toArray(new String[] {}));
factory.setDataSource(dataSource());
factory.setJpaDialect(new EclipseLinkJpaDialect());
Properties props = jpaProperties();
factory.setJpaProperties(props);
return factory;
}
一个简化的示例如下:
BooleanExpression boolExpr = Expressions.stringTemplate("replace({0},QTransaction.transaction.postingText).like("%" + filter.getPostingText() + "%");
transactionRepository.findAll(boolExpr);
日志显示:
An exception occurred while creating a query in EntityManager:
Exception Description: Syntax error parsing [select transaction
from Transaction transaction
where replace(transaction.postingText,'u') like ?1 escape '!'].
[54,115] The expression is not a valid conditional expression.
解决方法
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