问题描述
我正在为一个项目制作agario克隆，我想知道在pygame中绘制许多点的最快方法。
from pygame import *
import random as rd
x = rd.randint(100,700)
y = rd.randint(100,500)
# I would like to draw about 50 dots of this type.
dot = draw.circle(screen,(0,0),(x,y),5)
解决方法
以下是使用pygame绘制圆圈的一些基本代码：
import pygame as pg
import random as rd
pg.init() # initialize pygame
screen = pg.display.set_mode((500,500)) # create main screen
for ctr in range(25): # 25 circles
x = rd.randint(50,450)
y = rd.randint(50,450)
# I would like to draw about 50 dots of this type.
dot = pg.draw.circle(screen,(100,200,100),(x,y),15)
pg.display.update() # update screen
while True: # main pygame loop,always include this
for event in pg.event.get(): # required for OS events
if event.type == pg.QUIT: # user closed window
pg.quit()
输出
使用简单的python "for" loop with a "range"的任何简单方法：
当循环迭代时，它执行循环主体的内容，变量i从0递增到 N-1 （即49）。变量i可以是任何有效的变量名，但是对于简单的编号循环，通常使用i，j和k。
from pygame import *
import random as rd
# Draw 50 dots
for i in range( 0,50 ):
x = rd.randint(100,700)
y = rd.randint(100,500)
dot = draw.circle(screen,(0,0),5)
如果要在主应用程序循环中连续绘制相同的圆，则必须生成随机位置列表：
import pygame as pg
import random as rd
pg.init()
screen = pg.display.set_mode((800,600))
cpts = []
for i in range(25):
x = rd.randint(100,500)
cpts.append((x,y))
run = True
while run:
for event in pg.event.get():
if event.type == pg.QUIT:
run = False
for cpt in cpts:
pg.draw.circle(screen,(255,255,255),cpt,15)
pg.display.update()
有关最低pygame应用程序的信息，请参见Pygame unresponsive display的答案。
,我开设了一个点班：
import pandas as pd
df = pd.DataFrame({'time':['2019-10-19 19:23:00','2019-10-19 19:24:00','2019-10-19 19:25:00'],\
'lon':[48.80,48.801,48.8018],\
'lat':[2.13,2.130,2.12],\
'hilbert'=[4578,4577,4521]})
print(df)
然后我制作了一个数组，并生成class Dot():
SIZE = 5
def __init__(self,x,y):
self.x = x
self.y = y
def draw(self):
draw.circle(screen,self.color,(self.x,self.y),Dot.SIZE)
，如下所示：
NUMBER_OF_DOTS，并在dots = []
for i in range(NUMBER_OF_DOTS):
x = rd.randint(100,500)
dots.append(Dot(x,y))
循环中用白色填充整个场景后重新绘制：
为True时： screen.fill（（255，255，255）） ... 对于点中的点： dot.draw（）
整个来源：
while 