Python URLencode问题

问题描述

我正在尝试修改ANKI插件.py文件，以便能够解析牛津大学的单词

from urllib.parse import urlencode
qs = urlencode({"q": "come along"})

URL = "https://www.oxfordlearnersdictionaries.com/search/english/?{}"

print(URL.format(qs))

我的输出

“ https://www.oxfordlearnersdictionaries.com/search/english/?q=come+along”

但实际上输出应该是这样的

“ https://www.oxfordlearnersdictionaries.com/definition/english/come-along?q=come+along”

我是初学者，如何克服这个问题

#-- coding:utf-8 --
import random
from ..base import *

import requests
from bs4 import BeautifulSoup
from time import sleep
from random import randint



@register(u'Oxford_Article')
class Oxford_Article(WebService):

    def init(self):
        super(Oxford_Article,self).init()

    def _get_from_api(self):
        sleep(randint(1,3))
        
        param = {"q": "come along"}
        qs = urlencode(param)
        param['q'] = param['q'].replace(' ','-')
        URL = "https://www.oxfordlearnersdictionaries.com/definition/english/{}?{}"
        
        data = self.get_response(URL.format(param['q'],qs))
        soup = parse_html(data)
        result = {
            'Article': u'',}

        # Article
        element = soup.find('div',id='entryContent')
        for s in element.select('script'):
            s.extract()
        if element:
            result['Article'] = u''.join(str(e) for e in element.contents)


        return self.cache_this(result)

    @export([u'entryContent',u'Article definition'])
    def fld_definate(self):
        return self._get_field('Article')

解决方法

您可以做到

from urllib.parse import urlencode
param = {"q": "come along"}
qs = urlencode(param)
param['q'] = param['q'].replace(' ','-')
URL = "https://www.oxfordlearnersdictionaries.com/definition/english/{}?{}"
print(URL.format(param['q'],qs))

,

如果您在解析数据时遇到错误

只需替换此代码

setNames(keep_names,keep_names)

使用此代码

data = self.get_response(URL.format(param['q'],qs))
soup = parse_html(data)

也不要忘记导入此

page = urllib.request.urlopen(URL.format(param['q'],qs))
soup = BeautifulSoup(page)