使用SQL的同类群组表

问题描述

请提供一篇介绍使用SQL进行客户保留分析的指南的文章 并且我已经应用了解释的SQL代码，但是我总是会出错

以下代码应通过使用同类群组并通过首次访问定义每个用户，然后查看他们如何随时间返回，来分析用于分析客户保留率的同类群组表：first_month，new_users，retention_month，retained，retention_percent

WITH first_visit AS
    (SELECT SUBS_ID,min(date_trunc('month',(CUST_LOCAL_START_DATE::DATE))) AS first_month
    FROM ANALYTICS.tmp.Rate_Plan_Hierarchy
    GROUP BY 1
),New_users AS
    (SELECT first_month,count(DISTINCT SUBS_ID) AS new_users
    FROM first_visit
    GROUP BY 1)             
SELECT first_month,new_users,retention_month,retained,retention_percent
FROM   (SELECT first_month,( visit_tracker.visit_month - visit_log.visit_month ) AS
              retention_month,Count(DISTINCT visit_tracker.SUBS_ID) 
AS            
              retained,Count(DISTINCT visit_tracker.SUBS_ID)/new_users 
AS 
              retention_percent
        FROM ANALYTICS.tmp.Rate_Plan_Hierarchy visit_log
     LEFT JOIN ANALYTICS.tmp.Rate_Plan_Hierarchy  AS visit_tracker
            ON visit_log.SUBS_ID = visit_tracker.SUBS_ID
             AND date_trunc('month',CAST (visit_log.CUST_LOCAL_START_DATE AS DATE)) < date_trunc('month',CAST (visit_tracker.CUST_LOCAL_START_DATE AS DATE))
              LEFT JOIN new_users
                 ON new_users.first_month = first_visit.first_month
GROUP BY 1,2)t

我猜这是一个错误，我无法理解From子句上应该有什么tbale，而Left Join上应该是什么

     LEFT JOIN ANALYTICS.tmp.Rate_Plan_Hierarchy  AS visit_tracker
            ON visit_log.SUBS_ID = visit_tracker.SUBS_ID
             AND date_trunc('month',CAST (visit_tracker.CUST_LOCAL_START_DATE AS DATE))
              LEFT JOIN new_users
                 ON new_users.first_month = first_visit.first_month

解决方法

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