问题描述
$count=0;
while($row = pg_fetch_assoc($result)){
$sql=("INSERT INTO joblist (job_no,billed,completed,paid,paid_amount,inv_no,invoice,type,o_submitted,approval_date,gals,jobtype,name,state,region,territory)
VALUES (?,?,?) ON DUPLICATE KEY UPDATE
job_no=VALUES(job_no),billed=VALUES(billed),completed=VALUES(completed),paid=VALUES(paid),paid_amount=VALUES(paid_amount),inv_no=VALUES(inv_no),invoice=VALUES(invoice),type=VALUES(type),o_submitted=VALUES(o_submitted),approval_date=VALUES(approval_date),gals=VALUES(gals),jobtype=VALUES(jobtype),name=VALUES(name),state=VALUES(state),region=VALUES(region),territory=VALUES(territory)");
$stmt = $conn->prepare($sql);
$stmt->bind_param("ssssssssssssssss",$job_no,$billed,$completed,$paid,$paid_amount,$inv_no,$invoice,$type,$o_submitted,$approval_date,$gals,$jobtype,$name,$state,$region,$territory);
$stmt->execute();
$count++;
}
问题是,我无法在更新的行和插入的行之间进行解密。有办法吗? 我知道我可以使用受影响的行功能,但是如果更新/插入,它读取的内容相同。有任何想法吗?谢谢!
解决方法
您正在寻找带有RETURNING
子句的UPSERT
。
考虑到下表中的记录..
CREATE TEMPORARY TABLE t
(id INT PRIMARY KEY,name TEXT);
INSERT INTO t VALUES (1,'elgar'),(2,'bach'),(3,'brahms');
..您可以使用UPSERT
来捕获主键冲突,并要求查询返回受影响的记录。您可以将此插入内容放在CTE
中,并用新的查询计数。以下查询将插入两个已经存在的主键(1
和2
)和一个新的主键(4
):
WITH j (affected_rows) AS (
INSERT INTO t VALUES (1,'edward'),'johann sebastian'),(4,'schubert')
ON CONFLICT (id) DO UPDATE SET name = EXCLUDED.name
RETURNING *
) SELECT count(affected_rows) FROM j;
count
-------
3
亲自查看结果:-)
SELECT * FROM t ORDER BY id;
id | name
----+------------------
1 | edward
2 | johann sebastian
3 | brahms
4 | telemann