如何简化下面的SQL并提高性能？

问题描述

我试图使用嵌入式视图仅提取一行八列。

但是，有很多重叠。我不擅长使用PL / SQL。

如何简化SQL代码并提高查询性能？

我在“ CARD_NUM”列和“ CARD_TRANSACTION_TIME”列中创建了INDEX。
性能有了很大的提高，但是拥有1000万个数据时，仍然存在延迟。

感谢您的帮助。

WITH WHOLE AS (SELECT CARD_TRANSACTION_TIME,CARD_TRANSACTION_AMOUNT,CARD_TRANSACTION_CONTENT,INDUSTRY_CODE
                FROM CARD_TRANSACTION_TEST01
                WHERE CARD_NUM IN(SELECT CARD_NUM FROM CARD_CONTRACT_TEST01 WHERE RESI_NUM = '9203101937988')
                      AND TO_CHAR(CARD_TRANSACTION_TIME,'YYYY') = '2020' 
                      AND TO_CHAR(CARD_TRANSACTION_TIME,'MM') = '01'
                      
                UNION ALL
                
                SELECT CARD_TRANSACTION_TIME,INDUSTRY_CODE
                 FROM OPEN_CARD_TRANSACTION_TEST01     
                 WHERE RESI_NUM = '9203101937988'
                      AND TO_CHAR(CARD_TRANSACTION_TIME,'MM') = '01'    
                      AND MEANS IN('cardOne','cardTwo')
                )
SELECT SUBQUERY1.RESULT AS TYPE1,SUBQUERY2.RESULT AS "TYPE2",SUBQUERY3.RESULT AS "TYPE3",SUBQUERY4.RESULT AS "TYPE4",SUBQUERY5.RESULT AS "TYPE5",SUBQUERY6.RESULT AS "TYPE6",SUBQUERY7.RESULT AS "TYPE7",SUBQUERY8.RESULT AS "TYPE8"
FROM (SELECT * 
       FROM (SELECT SUM(RESULT) AS RESULT
             FROM(
                    SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
                    FROM WHOLE
                    GROUP BY INDUSTRY_CODE
                    HAVING INDUSTRY_CODE IN('I1','I2')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL))
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY1,(SELECT * 
       FROM (SELECT SUM(RESULT) AS RESULT
             FROM(
                    SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
                    FROM WHOLE
                    GROUP BY INDUSTRY_CODE
                    HAVING INDUSTRY_CODE IN('I4','I5','I6')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL))
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY2,(SELECT * 
       FROM (SELECT SUM(RESULT) AS RESULT
             FROM(
                    SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
                    FROM WHOLE
                    GROUP BY INDUSTRY_CODE
                    HAVING INDUSTRY_CODE IN('I7','I8')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL))
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY3,(SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I9')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY4,(SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I10')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY5,(SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I11')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY6,(SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I12')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY7,(SELECT * 
       FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
             FROM WHOLE
             GROUP BY INDUSTRY_CODE
             HAVING INDUSTRY_CODE IN('I13')
             
             UNION ALL
             
             -- SELECT NULL AS NUM
             SELECT 0 AS RESULT
             FROM DUAL)
       WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY8
WHERE ROWNUM <=1;

解决方法

由于您对所有子查询具有相同的分组依据，因此我简化了查询，我们可以只使用条件聚合来代替多个子查询。

您能否检查一下，因为由于架构对象而无法从句法上检查查询的有效性。

with whole as 
 (
  select card_transaction_time,card_transaction_amount,card_transaction_content,industry_code
    from card_transaction_test01
   where card_num in (select card_num from card_contract_test01 where resi_num = '9203101937988')
     and extract(year from card_transaction_time) = 2020
     and extract(month from card_transaction_time) = 1
  union all
  select card_transaction_time,industry_code
     from open_card_transaction_test01     
   where resi_num = '9203101937988'
     and extract(year from card_transaction_time) = 2020
     and extract(month from card_transaction_time) = 1
     and means in('cardOne','cardTwo')
 )
select result1 as TYPE1,result2 as TYPE2,result3 as TYPE3,result4 as TYPE4,result5 as TYPE5,result6 as TYPE6,result7 as TYPE7,result8 as TYPE8
from 
(
  select sum(case when industry_code in ('I1','I2') then card_transaction_amount else 0 end) as result1,sum(case when industry_code in ('I4','I5','I6') then card_transaction_amount else 0 end) as result2,sum(case when industry_code in ('I7','I8') then card_transaction_amount else 0 end) as result3,sum(case when industry_code in ('I9') then card_transaction_amount else 0 end) as result4,sum(case when industry_code in ('I10') then card_transaction_amount else 0 end) as result5,sum(case when industry_code in ('I11') then card_transaction_amount else 0 end) as result6,sum(case when industry_code in ('I12') then card_transaction_amount else 0 end) as result7,sum(case when industry_code in ('I13') then card_transaction_amount else 0 end) as result8
    from whole
  group by industry_code
);