问题描述
我有4个按键的字典列表
dict_list = [
{'key1': 'a','key2':'b','key3':'p','key4':'q' },{'key1': 'a','key4':'r' },'key2':'c','key2':'d','key4':'q' }
]
我的abc类如下
class abc:
def __init__(self,val1,val2,val3,val4)
self.val1 = val1
self.val2 = val2
self.val3 = val3
self.val4 = val4
@classmethod
def from_resultdict(cls,result):
return cls(result['key1'],result['key2'],result['key3'],result['key4'])
我得到带有以下代码段的列表[abc]
return [abc.from_resultdict(r) for r in dict_list]
我现在想添加一个class2用于根据key1和key2的值对对象列表进行分组
class class2:
def __init__(self,value1,value2)
self.value1 = value1
self.value2 = value2
self.list_of_abcs: List[abc]
我想为dict_list创建3个class2对象,例如
object1 {
value1 = a
value2 = b
list_of_abcs = [abc_object1,abc_object2]
}
object2 {
value1 = a
value2 = c
list_of_abcs = [abc_object3,abc_object4]
}
object3 {
value1 = a
value2 = d
list_of_abcs = [abc_object5]
}
我该如何实现?
解决方法
让我们暂时忽略这些类;您可以与我们的好朋友collections.defaultdict
进行分组:
import collections
from pprint import pprint
dict_list = [
{'key1': 'a','key2': 'b','key3': 'p','key4': 'q'},{'key1': 'a','key4': 'r'},'key2': 'c','key2': 'd','key4': 'q'}
]
groups = collections.defaultdict(list)
for d in dict_list:
groups[(d['key1'],d['key2'])].append(d)
pprint(dict(groups))
输出
{('a','b'): [{'key1': 'a','key4': 'r'}],('a','c'): [{'key1': 'a','d'): [{'key1': 'a','key4': 'q'}]}
从那里,您可以根据需要将输出(for group_key,members in groups.items()
)包装到类/对象中。
为dict
对象创建一个Class2
,以便为每个Abc
对象找到正确的对象。
class Class2:
def __init__(self,value1,value2)
self.value1 = value1
self.value2 = value2
self.list_of_abcs = []
objects = {}
for abc in abc_list:
key = (abc.val1,abc.val2)
if key not in objects: # create a Class2 instance if it doesn't exist yet
objects[key] = Class2(key[0],key[1])
# append the abc-object to the correct Class2 instance
objects[key].list_of_abcs.append(abc)