如何使用Spring Boot使用OAuth1.0和自定义标头对API进行身份验证

问题描述

我正在OAuth1.0授权过程中,这是Spring引导中的Java代码

package com.example.demo;

import com.mgiorda.oauth.OAuthConfig;
import com.mgiorda.oauth.OAuthConfigBuilder;
import com.mgiorda.oauth.OAuthSignature;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.http.*;
import org.springframework.web.client.RestTemplate;
//import com.example.demo.testsign;
import java.util.Collections;


@SpringBootApplication
@ComponentScan(basePackages = {"com.example.demo.controller"})
@Configuration
@EnableAutoConfiguration

public class TestapiApplication {
    public  static String testm() {

        OAuthConfig oauthConfig = new OAuthConfigBuilder("CONSUMER KEY","CONSUM_SECRET_KEY")
                .setTokenKeys("ACCESS TOKEN","SECRET TOKEN")
                .build();

        OAuthSignature signature = oauthConfig.buildSignature(com.mgiorda.oauth.HttpMethod.GET,url)
                .addQueryParam("aParam","aValue")
                .addFormUrlEncodedParam("myParam","anotherValue")
                .create();
        return signature.getAsHeader();
    }

    public static void main(String[] args) {
        String val = testm();
        //System.out.println(val);
        // request url
        String url = "htpps://khjfskdhf.com";

// create an instance of RestTemplate
        RestTemplate restTemplate = new RestTemplate();

// create headers
        HttpHeaders headers = new HttpHeaders();
// set `Content-Type` and `Accept` headers
        headers.setContentType(MediaType.APPLICATION_JSON);
        headers.setAccept(Collections.singletonList(MediaType.APPLICATION_JSON));
// example of custom header

        headers.set(HttpHeaders.AUTHORIZATION,val);
        System.out.println(headers);
// build the request
        httpentity request = new httpentity(headers);

// make an HTTP GET request with headers
        ResponseEntity<String> response = restTemplate.exchange(
                url,HttpMethod.GET,request,String.class
        );

// check response
        if (response.getStatusCode() == HttpStatus.OK) {
            System.out.println("Request Successful.");
            System.out.println(response.getBody());
        } else {
            System.out.println("Request Failed");
            System.out.println(response.getStatusCode());
        }
    }

}

我已经使用签名方法创建了标头,并将其传递给我的main方法以获得授权。但是我收到404 Not Found错误,这是错误消息,

08:13:17.464 [main] DEBUG org.springframework.web.client.RestTemplate - Response 404 NOT_FOUND
Exception in thread "main" org.springframework.web.client.HttpClientErrorException$NotFound: 404 Not Found: [no body]
    at org.springframework.web.client.HttpClientErrorException.create(HttpClientErrorException.java:113)
    at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:184)
    at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:125)
    at org.springframework.web.client.ResponseErrorHandler.handleError(ResponseErrorHandler.java:63)
    at org.springframework.web.client.RestTemplate.handleResponse(RestTemplate.java:782)
    at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:740)
    at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:674)
    at org.springframework.web.client.RestTemplate.exchange(RestTemplate.java:583)
    at com.example.demo.TestapiApplication.main(TestapiApplication.java:61)

谁能让我知道为什么它对我不起作用。我真的很难完成这个工作。有什么建议吗?

谢谢, 般若

解决方法

我通过提供URL参数值解决了该问题,并且还为标头创建了自定义唱歌请求方法。

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