Flutter请求“ FabricType”的实例 json.encodefabricList？

问题描述

我正在多次选择中发送列表类型的帖子请求。我在制作json.encode时遇到问题。我的代码在这里。

型号

import 'dart:convert';
    
class FabricType {
  String name;
  String apiName;
  int value;
  String uuid;

  FabricType({this.name,this.apiName,this.value,this.uuid});

  factory FabricType.fromJson(Map<String,dynamic> json) {

    return FabricType(
      name: json['name'],apiName: json['apiName'],value: json['value'],uuid: json['uuid'],);
  }

  Map toMap() {
    var map = new Map<String,dynamic>();
    map["name"] = name;
    map["apiName"] = apiName;
    map["value"] = value;
    map["uuid"] = uuid;

    return map;
  }

}

对于

List<FabricType> fabricList = List();
subContentList(List subContentList,List selectedUUid) {
  fabricList.clear();
  for (int i = 0; i < selectedUUid.length;i++) {
    fabricType = new FabricType();
    fabricType.uuid = selectedUUid[i].toString();
    fabricType.name = "test";
    fabricType.apiName = "colorTypes";
    fabricList.add(fabricType);
  }
}

发布请求

Response res = await http.post(
    BaseApi + EndPoint,headers: Header().header,body:json.encode(fabricList) //Bug Here
);
print(res.body);
String statusCode = res.statusCode.toString();
print("Ad Sub Content Status Code: " + statusCode);  
return res;

错误消息

I/flutter (15808): [Instance of 'FabricType',Instance of 'FabricType']

问题是“编码”；问题是什么？我该怎么办？

解决方法

方法应为toJson，而不是toMap，将其替换

  Map<String,dynamic> toJson() {
    var map = new Map<String,dynamic>();
    map["name"] = name;
    map["apiName"] = apiName;
    map["value"] = value;
    map["uuid"] = uuid;

    return map;
  }