如何拉我倒数第二个

问题描述

运行git log时，我看到：

commit d0fa4410393w92ce6ede2ea26fa2fb74z2e5f1bz (HEAD -> notificationControls,origin/notificationControls)
Author: stufezic-dev <[e-mail]>
Date:   Sat Sep 19 12:32:45 2020 +0545

    lockscreen controls working,notification updates yet to fix

commit 2e11d85350a741d6992875e949a0a77abbeb8fde (mainadjust,commitBranch)
Author: stufezic-dev <[e-mail]>
Date:   Tue Sep 15 23:30:27 2020 +0545

    notification and lockscreen controls using mediaSession: initiated  
  
commit 2e11d85350a741d6992875e949a0a77abbeb8fde (mainadjust,commitBranch)
Author: stufezic-dev <[e-mail]>
Date:   Tue Sep 14 23:30:27 2020 +0545

    notification and lockscreen controls using mediaSession: initiated  
  
...

如何拉倒数第二个或倒数第三个提交，而不是最近的提交？我只知道1条命令：git pull master origin，并且正在考虑如何提取任何提交而不是最新的提交。

解决方法

git pull origin master等效于git fetch origin，后跟git merge origin/master。

如果您要合并分支中origin/master以外的其他内容（例如：origin/master之前的第三次提交），请使用git fetch而不是git pull：

git fetch

# inspect the history
git log --graph origin/master HEAD

# merge whatever commit you want into your branch
git merge eacf32