口才构建器实例上不存在属性[id]

问题描述

我正在尝试获取评论，并且它在laravel API中得到答复，我尝试按照以下方式处理，并遇到此错误，该如何解决？ 这是我的控制器：

 public function postSinglePage(Request $request)
{
    $post_id=$request->get('post_id');
    $post = Post::where('id',$post_id)->where('status','=',1)->get();
    return response([
        "posts" => GetPostsSinglePageData::collection($post),]);


}

这是我要发布的资源集及其评论：

public function toArray($request)
{

    return [
        'post_id' => $this->id,"name" => $this->post_title,"excerpt" => $this->post_excerpt,"thumbnail" => $this->getFirstMediaUrl("images"),"logo" => $this->getFirstMediaUrl("images"),'comment_count'=>getCommentCount($this->id),'comments'=> new CommentCollection(Comment::select('*')->where('post_id',$this->id)),"like" => DB::table("like_tb")->select('like_dislike')
            ->where("type_like",'post')
            ->where('related_id',$this->id)
            ->get(),"share" => DB::table("share_tb")->select("share_number")
            ->where('type','post')
            ->where("related_id",];
}

这是评论集：

public function toArray($request)
{


    return [
        'commentId'=>$this->id,'courseId'=>$this->post_id,'commentDate'=>$this->date,'commentText'=>$this->body,'userId'=>$this->user_id,'replays'=>ReplyCommentCollection::collection(\App\Models\Comment\ReplyComment::where('comment_id',$this->id)->get()),'users'=>UserInfoCollection::collection(User::where('id',$this->user_id)->get()),];
}

解决方法

$ this-> id 在其他内部函数中不起作用，您必须这样编写：

  public function toArray($request)
    {
        $comments=Comment::select('*')->where('post_id',$this->id)->get();
        $commentCollection= CommentCollection::collection($comments);
        return [
            'post_id' => $this->id,"name" => $this->post_title,"excerpt" => $this->post_excerpt,"thumbnail" => $this->getFirstMediaUrl("images"),"logo" => $this->getFirstMediaUrl("images"),'comment_count'=>getCommentCount($this->id),'comments'=> $commentCollection,"like" => DB::table("like_tb")->select('like_dislike')
                ->where("type_like",'=','post')
                ->where('related_id',$this->id)
                ->get(),"share" => DB::table("share_tb")->select("share_number")
                ->where('type','post')
                ->where("related_id",];
    }