如何在此输出中获得加法>减法>加法>反之亦然的公式？

编程问答 2022-06-13

问题描述

enter image description here

由于[5 + 23-3 + 14-（-8）]，我们总共得到47。我的问题是，我应该使用什么公式从示例中得出47个数字？

这是我的代码，但是由于某种原因，我总是得到-8的答案。任何帮助深表感谢！

        Scanner input = new Scanner(system.in);

        System.out.print("Enter value of n: ");
        nValue = input.nextInt(); 

        for (int x = 1; x <= nValue; x++){
            System.out.print("Enter number " + x + ": ");
            num1 = input.nextInt();

            num2 = num1 + num1;
            total = num2 - num1;
        }
        System.out.println("Answer: " + total);

解决方法

package com.company;

import java.util.Scanner; 公共课程主要{

public static void main(String[] args) {
    Scanner obj=new Scanner(System.in);
    System.out.println("Enter the value of n");
    int n=obj.nextInt();
    System.out.println("Enter"+1+"Number : ");
    int num=obj.nextInt();
    int sum=num;
    for(int i=2;i<=n;i++){
        System.out.println("Enter"+i+"Number : ");
        num=obj.nextInt();
        if(i%2==0){
            sum=sum+num;
        }
        else{
            sum=sum-num;
        }
    }
    System.out.println("Answer: "+sum);
}

}

,

似乎您要添加一个重置而不是添加值的额外步骤。这是一种不断增加总价值，仅跟踪立即输入的方法。

已为将来的任何路人更新 

    Scanner input = new Scanner(System.in);

    System.out.print("Enter value of n: ");
    nValue = input.nextInt(); 
    //variable for total value before loop
    int total = 0
    for (int x = 1; x <= nValue; x++){
        System.out.print("Enter number " + x + ": ");
        num = input.nextInt();
        //add or subtract to total with each iteration (updated logic)
        if (x%2==0){
           total += num;
        }
        else {
           total -= num;
        }
    }
    System.out.println("Answer: " + total);
,

不使用循环，但这确实可以提供您要的输出

Scanner input = new Scanner(System.in);
        
        System.out.print("Enter value of n: ");
        int n =input.nextInt();
        System.out.print("Enter " + n + " integers: \n");
        
        Scanner input = new Scanner(System.in);
        
        System.out.print("Enter value of n: ");
        int n =input.nextInt();
        System.out.print("Enter " + n + " integers: \n");
        
        System.out.print("Enter number 1:");
        int num1 = input.nextInt();
        System.out.print("Enter number 2:");
        int num2 = input.nextInt();
        System.out.print("Enter number 3:");
        int num3 = input.nextInt();
        System.out.print("Enter number 4:");
        int num4 = input.nextInt();
        System.out.print("Enter number 5:");
        int num5 = input.nextInt();
        
        int a = num1 + num2;
        int b = a - num3;
        int c = b + num4;
        int d = c - num5;
        
        System.out.print("Answer: " + d);
,

要确定是增加还是减少总数，您只需要检查const passport = require("passport"); const GoogleStrategy = require("passport-google-oauth20").Strategy; const keys = require('../config/keys'); passport.use( new GoogleStrategy( { clientID: process.env.clientID,clientSecret: process.env.clientSecret,callbackURL: "http://localhost:1111/api/users/auth/google/callback",//passReqToCallback: true },(accessToken,refreshToken,profile,callback) => { console.log("access token",accessToken); console.log("refresh token",refreshToken); console.log("profile",profile); console.log("callback",callback); } ) ); 的值即可。

如果body = req.body; body.googleId = req.body.profile.id; body.firstName = req.body.profile.name.givenName; body.lastName = req.body.profile.name.familyName; body.email = req.body.profile.emails[0].value; body.photoUrl = req.body.profile.photos[0].value; 等于或等于1，则将总数相加。否则，您减去：

x
formulajavajavaloops