检查文本中是否存在2个或多个用括号括起来的字符或数字，并且至少第一个字符大写

问题描述

contains_acronym函数检查文本中是否存在2个或多个用括号括起来的字符或数字，并且至少第一个字符为大写字母（如果是字母），如果满足条件则返回True，否则返回False。例如，“即时消息（IM）是用于基于文本的通信的一组通信技术”，由于（IM）满足匹配条件，因此应返回True。”在此函数中填写正则表达式：

import re
def contains_acronym(text):
  pattern = ___ 
  result = re.search(pattern,text)
  return result != None

print(contains_acronym("Instant messaging (IM) is a set of communication technologies used for text-based communication")) # True
print(contains_acronym("American Standard Code for @R_642_4045@ion Interchange (ASCII) is a character encoding standard for electronic communication")) # True
print(contains_acronym("Please do NOT enter without permission!")) # False
print(contains_acronym("PostScript is a fourth-generation programming language (4GL)")) # True
print(contains_acronym("Have fun using a self-contained underwater breathing apparatus (Scuba)!")) # True

我尝试了这种模式，但不适用于所有给定的输入情况，

pattern = r"\(([A-Z0-9_]+)\)"

解决方法

最终尝试使用以下模式，并且使用以下代码涵盖了所有上述场景，

  import re
  def contains_acronym(text):
  pattern = r"\([A-Za-z0-9]{2,}\)"
  result = re.search(pattern,text)
  return result != None

print(contains_acronym("Instant messaging (IM) is a set of communication technologies used for text-based communication")) # True
print(contains_acronym("American Standard Code for Information Interchange (ASCII) is a character encoding standard for electronic communication")) # True
print(contains_acronym("Please do NOT enter without permission!")) # False
print(contains_acronym("PostScript is a fourth-generation programming language (4GL)")) # True
print(contains_acronym("Have fun using a self-contained underwater breathing apparatus (Scuba)!")) # True

您好，正则表达式几乎是正确的，只是忘记了它必须具有至少2 ，因此只需将第一个范围设为字符串的恒定部分，然后用

重复相同的匹配即可。

带有+（一个或多个）的小写字母

模式= r“（（[[A-Z0-9 _] [A-Za-z0-9 _] +））”

import re
def contains_acronym(text):
  pattern = r'\([A-Za-z0-9]{2,}\)' 
  result = re.search(pattern,text)
  return result != None

print(contains_acronym("Instant messaging (IM) is a set of communication technologies used for text-based communication")) # True
print(contains_acronym("American Standard Code for Information Interchange (ASCII) is a character encoding standard for electronic communication")) # True
print(contains_acronym("Please do NOT enter without permission!")) # False
print(contains_acronym("PostScript is a fourth-generation programming language (4GL)")) # True
print(contains_acronym("Have fun using a self-contained underwater breathing apparatus (Scuba)!")) # True

import re
def contains_acronym(text):
  pattern = r"\([A-Z0-9][A-Z0-9a-z]+\)"
  result = re.search(pattern,text)
  return result != None

将此用作模式

`pattern = r"\(\w.*\w\)" `

“w”表示字母和数字

python-3.x python-regex