问题描述
所以我写出了整个程序，我的循环用于计算指数在自己的程序中工作，但是当我逐步执行该程序时，它们并没有按照我希望的方式多次运行并输出程序给出的全为0。
这是代码： 编辑：我已经将代码更新为我目前拥有的代码，最后添加了除法功能。目前，我正在为前三个循环集获取适当的值。这意味着我得到了f的正确值，但是g的第二个分量d ^ w没有吐出正确的值。
##designed and written by Aidan Rosser-Jones
.data #data needed
A : .word 0
B : .word 0
C : .word 0
D : .word 0 ## A-D are the base values that the user inputs
x : .word 8
y : .word 5
z : .word 7
w : .word 5 ## x-w are the exponents with hardcoded student ID numbers
userPrompt : .asciiz "Please enter four integers seperated by an enter key." ## prompting the user
F : .asciiz "f(decimal) : " ## result for F in base 10
binaryF : .asciiz "f(binary) : " ## result for F in base 2
G : .asciiz "g(decimal) : " ## result for G in base 10
binaryG : .asciiz "g(binary) : " ## result for G in base 2
quotientH : .asciiz "h quotient : " ## quotient result for H
remainderH : .asciiz "h remainder : " # remainder result for H
skipLine : .asciiz "\n" ## for printing a new line
.text ##switching back to code section
.globl main
main:
#first we must prompt the user for the four integers
la $a0,userPrompt #loading the prompt from data section into $a0
li $v0,4 #syscall for printing a string
syscall # this actually does the printing
#Now we gotta read the first integer
li $v0,5
syscall
lw $s4,A #loading the address of variable a into $t0
move $s4,$v0 #copying the user input to $t0
#time to read the second integer (basically second verse,same as the first for the next 3)
li $v0,5
syscall
lw $s5,B
move $s5,$v0
#3rd integer
li $v0,5
syscall
lw $s6,C
move $s6,$v0
#4th integer
li $v0,5
syscall
lw $s7,D
move $s7,$v0
#time to do some calculations
#calculating a^x
move $t1,$s4 #loading address of A into $t1
##lw $t1,($t1) #loading the value of A into $t1
la $t2,x #loading address of x into $t2
lw $t2,($t2) #loading the value of x into $t2
#loop prep
move $t5,$t1 #answer = base
move $t6,$t1 #increment = base
li $t3,1 # i = 1
li $t4,1 # j = 1
For0:
ble $t2,$t3,Exit0 #for(i =1; i<x; i++)
addi $t3,1 #i++
li $t4,1 #resesting j to 1 so nested loop works properly
move $t6,$t5
j For1
For1:
ble $t1,$t4,For0 #for(j=1; j < A; j++)
add $t5,$t5,$t6 #answer+=increment
addi $t4,1 #j++
j For1
Exit0:
move $s0,$t5 #storing a^x in $s0
#calculating b^y
move $t1,$s5 #loading address of B into $t1
##lw $t1,($t1) #loading the value of B into $t1
la $t2,y #loading address of y into $t2
lw $t2,($t2) #loading the value of y into $t2
#loop prep
move $t5,1 # j = 1
For2:
ble $t2,Exit1 #for(i =1; i<y; i++)
addi $t3,$t5
j For3
For3:
ble $t1,For2 #for(j=1; j < B; j++)
add $t5,$t6 #answer+=increment
addi $t4,1 #j++
j For3
Exit1:
move $s1,$t5 #storing b^y in $s0
#calculating c^z
move $t1,$s6 #loading address of C into $t1
##lw $t1,($t1) #loading the value of C into $t1
la $t2,z #loading address of z into $t2
lw $t2,($t2) #loading the value of z into $t2
#loop prep
move $t5,1 # j = 1
For4:
ble $t2,Exit2 #for(i =1; i<z; i++)
addi $t3,$t5
j For5
For5:
ble $t1,For4 #for(j=1; j < c; j++)
add $t5,1 #j++
j For5
Exit2:
move $s2,$t5 #storing c^z in $s0
#calculating d^w
move $t1,$s6 #loading address of D into $t1
##lw $t1,($t1) #loading the value of D into $t1
la $t2,w #loading address of w into $t2
lw $t2,($t2) #loading the value of w into $t2
#loop prep
move $t5,1 # j = 1
For6:
ble $t2,Exit3 #for(i =1; i<w; i++)
addi $t3,$t5
j For7
For7:
ble $t1,For6 #for(j=1; j < D; j++)
add $t5,1 #j++
j For7
Exit3:
move $s3,$t5 #storing d^w in $s3
##THIS IS FOR TESTING PURPOSES ONLY
li $v0,1
move $a0,$s3
syscall
##CONCLUDING TEST CODE
#calculating and storing f = a^x + b^y
add $s0,$s0,$s1 #f = $s0
#calculating and storing g = c^z + d^w
add $s2,$s2,$s3 #g = $s2
#Now lets print out all of the data,starting with a fresh line to avoid confusion!
la $a0,skipLine
li $v0,4
syscall #skips a line
#printing f
la $a0,F
li $v0,4
syscall
li $v0,$s0
syscall #print f in decimal
#printing new line for organization
la $a0,4
syscall #skips a line
la $a0,binaryF
li $v0,35
move $a0,$s0
syscall #this should print the binary f
#printing new line for organization
la $a0,4
syscall #skips a line
#lets print g!
la $a0,G
li $v0,$s2
syscall #this should print decimal g
#printing new line for organization
la $a0,4
syscall #skips a line
#lets print g but binary this time!
la $a0,binaryG
li $v0,$s2
syscall
#Now we must calculate h = f/g
#division prep
# f = $s0
# g = $s2
add $t0,$zero,$s0 #copies the value of f into $t0
add $t1,$s1 #copies the value of g into $t1
add $t2,$zero #make $t2 the counter starting at 0
div_loop:
sle $t3,$t2,$t1 #checks if equal
beq $t3,end_divis
sub $t0,$t0,$t1
addi $t2,1
j div_loop
end_divis:
move $s6,$t2 # stores quotient in $s6
move $s7,$t0 # stores remainder in $s7
#Now its time to print the values for h
#printing new line for organization
la $a0,quotientH
li $v0,4
syscall # prints quotientH string
li $v0,$s6
syscall #print integer value for quotient H
#printing new line for organization
la $a0,remainderH
li $v0,4
syscall #print remainder H string
li $v0,$s7
syscall #print integer value for remainder H
#terminate the program
li $v0,10
syscall
如果有些评论不对，我深表歉意。我复制并粘贴了循环，然后更改了计算的存储位置和循环名称（出于跳转目的）以实现所需的功能。
当前我的输出如下：
请输入四个用Enter键分隔的整数。2 3 1个 2 1（这是d ^ w值的测试打印） f（十进制）：499 f（二进制）：00000000000000000000000111110011 g（十进制）：2 g（二进制）：00000000000000000000000000000010 商：244 h余数：-58793 -程序运行完毕-
如前所述，问题与我的循环有关，但是我一直盯着它看了一段时间，无法弄清楚是什么原因。由于我不到一周的学习MIPS的经验，任何帮助将不胜感激。
作为参考，这些循环是根据我编写的以下Java代码建模的：
/*
* Written by Aidan Rosser-Jones
*/
public class exponentLoop {
public static final int BASE = 5;
public static final int POWER = 6;
public static void main(String[] args) {
int answer = BASE;
int increment = BASE;
for(int i = 1; i < POWER; i++)
{
for(int j = 1; j < BASE; j++)
{
answer += increment;
}
increment = answer;
}
System.out.println(answer);
}
}
**对于这个项目，我们不允许使用任何种类的乘法指令或函数，这就是为什么代码以这种方式格式化
解决方法
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