问题描述
我正在尝试使句子从数组中两次选择随机项。第一项被暂时从数组中删除,因此无法再次选择,然后第二项也被随机选择并添加到句子中。然后,要重置它,以便以后可以再次执行此操作,请尝试将第一个选择的项重新添加到其初始数组中。
问题在于,当我这样做时,selectedWord1如我希望的那样在句子中显示为字符串,但是selectedWord2却显示了索引号。
array = ["word","another word","yet another word"];
/* put a random word from the array in its own value and then
remove it from the array so it can't be chosen in next step */
let chosenWord1 = array.splice(Math.random() * array.length,1)[0];
/* pick another random word from the same,altered array */
let chosenWord2 = Math.floor(Math.random() * array.length);
/* a function that puts a sentence on the webpage concatenating the strings
from chosenWord1 and chosenWord2 goes here. then... */
/* add back the prevIoUsly removed word so this process can repeat again
with the same items in the array as there was before anything was done to it */
array.splice(1,chosenWord1);
此外,如果我可以通过一些更明智的方式来构建此结构,请告诉我。我对此还很陌生。
解决方法
我不知道这是否是您所需要的,但这会重复提取两个随机单词,而不会从原始数组中取出它们。 for循环用于显示如何使用不同的单词。
const array = ["word","another word","yet another word"];
const randomNumber = (key) => Math.floor(Math.random() * key);
for (let i = 0; i < 10; i++) {
const { [randomNumber(array.length)]: wordOne,...rest } = array;
const { [randomNumber(array.length - 1)]: wordTwo } = Object.values(rest);
console.log(`${wordOne} and ${wordTwo}`);
}