Auditbeat-删除dockerd子进程规则

问题描述

我已经安装了Auditbeat,以便从VM发送有关ELK的信息。

Rules configuration:
# Identity changes.
-w /etc/group -p wa -k identity
-w /etc/passwd -p wa -k identity
-w /etc/gshadow -p wa -k identity
-w /etc/shadow -p wa -k identity
-w /etc/security/opasswd -p wa -k identity

## Unauthorized access attempts.
-a always,exit -F arch=b64 -S open,creat,truncate,ftruncate,openat,open_by_handle_at -F exit=-EACCES -k access
-a always,open_by_handle_at -F exit=-EPERM -k access

## All elevation of privileges is logged
-a always,exit -F arch=b64 -S setuid -F a0=0 -F exe=/usr/bin/su -F key=elevated-privs
-a always,exit -F arch=b64 -S setresuid -F a0=0 -F exe=/usr/bin/sudo -F key=elevated-privs
-a always,exit -F arch=b64 -S execve -C uid!=euid -F euid=0 -F key=elevated-privs

## Log all user commands
-a exit,always -F arch=b64 -F euid=0 -S execve -k user-commands

## Log all processes executed
-a always,exit -S execve,execveat -k executed-process

但是我在ELK中收到了所有进程,但我想从dockerd中过滤掉进程和子进程(如下所示)。

root       1074      1  3 Aug15 ?        1-11:17:28 /usr/bin/dockerd -H unix://
root       1312   1074  0 Aug15 ?        05:10:11  \_ containerd --config /var/run/docker/containerd/containerd.toml --log-level info
root       2612   1312  0 Aug15 ?        00:01:36  |   \_ containerd-shim -namespace moby -workdir /var/lib/docker/containerd/daemon/io.containerd.runtime.v1.linux/moby/8d0656e69919ad21390a8763552114a
root       2632   2612  0 Aug15 ?        00:00:00  |   |   \_ /pause
root       2718   1312  0 Aug15 ?        00:01:38  |   \_ containerd-shim -namespace moby -workdir /var/lib/docker/containerd/daemon/io.containerd.runtime.v1.linux/moby/3be9a09164477a5ddad974a9b7d0cdc
nfsnobo+   2735   2718  0 Aug15 ?        00:14:13  |   |   \_ /tiller
root       3943   1312  0 Aug15 ?        00:01:26  |   \_ containerd-shim -namespace moby -workdir /var/lib/docker/containerd/daemon/io.containerd.runtime.v1.linux/moby/56966f53cb30a304add50370f298a19
root       3961   3943  0 Aug15 ?        00:00:00  |   |   \_ /pause

是否可以通过规则从主流程中过滤出子流程?

谢谢

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