“;预期的”，“;正在运行JPA查询

问题描述

我有这个jpa查询

@Query(nativeQuery = true,value = "with\n"
            + "    validBonansasAssignation as (\n"
            + "        select aga.autorisation_bonansas_id,aga.autorisation_bonansa_assign_id as iBonansaAffectation_id,\n"
            + "               s.site_id as ISiteNoTypeBaseData_id,s.desc_court as iSiteNoTypeBaseData_nom,\n"
            + "               aga.dt_debut as iBonansaAffectation_dt_debut,aga.dt_fin as iBonansaAffectation_dt_fin\n"
            + "        from AUTORISATION_BONANSA_ASSIGNATION aga\n"
            + "        inner join site s on aga.site_id = s.site_id\n"
            + "        where ?1 between aga.dt_debut and aga.dt_fin\n"
            + "    )\n"
            + "select ag.AUTORISATION_BONANSAS_ID,ag.NOM,ag.PRENOM,ag.EULOGIN,ag.dt_Debut,ag.dt_Fin\n"
            + ",aga.iBonansaAffectation_id,aga.iSiteNoTypeBaseData_id,aga.iSiteNoTypeBaseData_nom\n"
            + ",aga.iBonansaAffectation_dt_debut,aga.iBonansaAffectation_dt_fin\n"
            + "from autorisation_bonansa ag\n"
            + "left join validBonansasAssignation aga on ag.autorisation_bonansas_id = aga.autorisation_bonansas_id\n"
            + "where ?1 between ag.dt_debut and ag.dt_fin\n"
            + "and ag.organisation_id = ?2")
List<AutoUsers> find(Date date,Long id);

但是运行测试时出现此错误：

org.springframework.orm.jpa.JpaSystemException: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.7.2.v20180622-f627448): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.h2.jdbc.JdbcsqlException: Syntax error in sql statement "WITH
    VALIDBONANSASASSIGNATION AS[*] (
        SELECT AGA.AUTORISATION_BONANSAS_ID,AGA.AUTORISATION_BONANSA_ASSIGN_ID AS IBONANSAAFFECTATION_ID,S.SITE_ID AS ISITENOTYPEBASEDATA_ID,S.DESC_COURT AS ISITENOTYPEBASEDATA_NOM,AGA.DT_DEBUT AS IBONANSAAFFECTATION_DT_DEBUT,AGA.DT_FIN AS IBONANSAAFFECTATION_DT_FIN
        FROM AUTORISATION_BONANSA_ASSIGNATION AGA
        INNER JOIN SITE S ON AGA.SITE_ID = S.SITE_ID
        WHERE ? BETWEEN AGA.DT_DEBUT AND AGA.DT_FIN
    )
SELECT AG.AUTORISATION_BONANSAS_ID,AG.NOM,AG.PRENOM,AG.EULOGIN,AG.DT_DEBUT,AG.DT_FIN,AGA.IBONANSAAFFECTATION_ID,AGA.ISITENOTYPEBASEDATA_ID,AGA.ISITENOTYPEBASEDATA_NOM,AGA.IBONANSAAFFECTATION_DT_DEBUT,AGA.IBONANSAAFFECTATION_DT_FIN
FROM AUTORISATION_BONANSA AG
LEFT JOIN VALIDBONANSASASSIGNATION AGA ON AG.AUTORISATION_BONANSAS_ID = AGA.AUTORISATION_BONANSAS_ID
WHERE ? BETWEEN AG.DT_DEBUT AND AG.DT_FIN
AND AG.ORGANISATION_ID = ? "; expected ".,("; sql statement:

解决方法

您能像下面那样设置nativeQuery = true并看看是否可行。

@Query(
  value = "SELECT * FROM USERS u WHERE u.status = 1",nativeQuery = true)

,

由JPA生成原始查询的方式形成了错误堆栈，我建议按如下所示进行更改并尝试，

我现在没有IDE可以以正确的格式实际修改查询，因此以SQL格式提供了查询，但目的是要在WITH子句中定义列，因为您会在错误中看到它像WITH VALIDBONANSASASSIGNATION AS[*] (这样生成的堆栈，而[*]之后的AS是Oracle无法识别并抛出语法错误的地方。

WITH VALIDBONANSASASSIGNATION 
(
  AUTORISATION_BONANSAS_ID,IBONANSAAFFECTATION_ID,ISITENOTYPEBASEDATA_ID,ISITENOTYPEBASEDATA_NOM,IBONANSAAFFECTATION_DT_DEBUT,IBONANSAAFFECTATION_DT_FIN
)
AS
(
  SELECT AGA.AUTORISATION_BONANSAS_ID,AGA.AUTORISATION_BONANSA_ASSIGN_ID AS IBONANSAAFFECTATION_ID,S.SITE_ID AS ISITENOTYPEBASEDATA_ID,S.DESC_COURT AS ISITENOTYPEBASEDATA_NOM,AGA.DT_DEBUT AS IBONANSAAFFECTATION_DT_DEBUT,AGA.DT_FIN AS IBONANSAAFFECTATION_DT_FIN
    FROM AUTORISATION_BONANSA_ASSIGNATION AGA
  INNER JOIN SITE S 
     ON AGA.SITE_ID = S.SITE_ID
  WHERE ? BETWEEN AGA.DT_DEBUT 
    AND AGA.DT_FIN
)
SELECT AG.AUTORISATION_BONANSAS_ID,AG.NOM,AG.PRENOM,AG.EULOGIN,AG.DT_DEBUT,AG.DT_FIN,AGA.IBONANSAAFFECTATION_ID,AGA.ISITENOTYPEBASEDATA_ID,AGA.ISITENOTYPEBASEDATA_NOM,AGA.IBONANSAAFFECTATION_DT_DEBUT,AGA.IBONANSAAFFECTATION_DT_FIN
FROM AUTORISATION_BONANSA AG
LEFT JOIN VALIDBONANSASASSIGNATION AGA 
  ON AG.AUTORISATION_BONANSAS_ID 
   = AGA.AUTORISATION_BONANSAS_ID
WHERE ? BETWEEN AG.DT_DEBUT AND AG.DT_FIN
  AND AG.ORGANISATION_ID = ?

我尝试了一下，看是否有效。