如何将标记文本数据的对象dtype转换为数字的int dtype我也尝试过.astype,pd.to_numeric,isinstancex,str

问题描述

这是我的电影评论数据集的片段,在文本列中被标记为数字:

enter image description here

如何将 #include <stdio.h> #include <unistd.h> #include <fcntl.h> #include <sys/types.h> #include <sys/wait.h> #include <string.h> #include <stdlib.h> int main(int argc,char *argv[]) { int fds[2]; int test[2]; int pid; pid_t child_a; char buffer[50],buff[50]; if(pipe(fds)) { perror("Pipe:"); exit(0); } if(pipe(test)) { perror("Pipe:"); exit(0); } child_a = fork(); if (child_a == 0) { //Child //CHANGED: No need to open file pointers here. Pipes are already open and accessed by file descriptor instead of file pointer. File pointers create trouble when used with pipes. 0 is file descriptor of stdin,1 for stdout. close(fds[1]); close(test[0]); dup2(fds[0],0); dup2(test[1],1); //CHANGED: There was an error with the command you wrote. //That's because ./sand arg will look for a 'sand' directory which doesn't exist //This line will throw warnings because execlp requires needs a command as the second argument,but in this case the filename is the command. //NOTE: before running quick.c,compile sand.c as sand.out and not a.out execlp("./sand.out",NULL); printf("Exec Error\n"); //this will only execute if execlp didn't run. Always have this line in your code to kNow what's happening. } else { // Parent // Wrap the pipes //Got rid of the file pointers close(fds[0]); close(test[1]); //CHANGE: fgets is only used with file pointers. While handling pipes,we work with file descriptors,with which read and write methods are used int n = read(0,buffer,50); //If this is new to you,I strongly recommend reading manual pages for read and write,but for right Now // The signature should be enough to understand - read/write(int file_descriptor,char *buffer,int number_of_bytes) write(fds[1],n); //MOST IMPORTANT: You need to wait for child after this point. Because test pipe doesn't have data yet which will be received by child. wait(NULL); //CHANGE: printf statements do not work well with buffere,because buffers are not terminated with null //%s specifier will always look for a null or print garbage //If you still want to use printf,look into $man bzero while((n = read(test[0],buff,50))>0) { write(1,n); } fflush(stdout); } return 0; } 列类型从对象转换为 #include <stdio.h> #include <unistd.h> #include <fcntl.h> #include <sys/types.h> #include <sys/wait.h> #include <string.h> #include <stdlib.h> #include <ctype.h> int main(int argc,char *argv[]) { char buffer[50]; int i = 0; int n = read(0,sizeof(buffer)); //changed fgets to read,to get number of bytes read. char chr; // Loop // we have number of bytes. So change while to for for (i=0;i<n;i++) { buffer[i] = toupper(buffer[i]); } write(1,n); //Changed fprintf to write to get rid of %s problem. //Again,to fill remaining places of buffer with null,look up bzero. //The reason I haven't done that is to not confuse you with so many changed methods. return 0; }

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