问题描述
无论是ESP8266还是ASP.NET Core,我都是菜鸟-非常感谢您在理解我做错事情方面的支持。
最底线:我正在尝试将数据从ESP8266发送到sql Azure。我已经基于tutorial构建了一个API,并且基于通过Postman进行的测试而成功完成了这一部分:我能够将JSON的JSON POST请求从Postman发送到API,并将数据存储到sql Azure。
我正在苦苦挣扎的是让ESP8266将JSON数据的POST请求提交到我的API。
我首先利用内置的HTTPS请求模板使其保持简单,但始终最终甚至连到API的连接都没有(根据响应代码)。为简单起见,我什至将GET请求保留在模板中,因为我认为暂时获取还是发布数据都没有关系,因为我只想确保先建立连接即可。知道为什么这行不通吗?
#include <ESP8266WiFi.h>
#include <WiFiClientSecure.h>
#ifndef STASSID
#define STASSID "***"
#define STAPSK "***"
#endif
const char* ssid = STASSID;
const char* password = STAPSK;
const char* host = "https://***.azurewebsites.net/api";
const int httpsPort = 443;
// Use web browser to view and copy
// SHA1 fingerprint of the certificate
const char fingerprint[] PROGMEM = "***"; // Fingerprint: 2020-09-30
void setup() {
Serial.begin(115200);
Serial.println();
Serial.print("connecting to ");
Serial.println(ssid);
WiFi.mode(WIFI_STA);
WiFi.begin(ssid,password);
while (WiFi.status() != WL_CONNECTED) {
delay(500);
Serial.print(".");
}
Serial.println("");
Serial.println("WiFi connected");
Serial.println("IP address: ");
Serial.println(WiFi.localIP());
// Use WiFiClientSecure class to create TLS connection
WiFiClientSecure client;
Serial.print("connecting to ");
Serial.println(host);
Serial.printf("Using fingerprint '%s'\n",fingerprint);
client.setFingerprint(fingerprint);
if (!client.connect(host,httpsPort)) {
Serial.println("connection Failed");
return;
}
String url = "/network";
Serial.print("requesting URL: ");
Serial.println(url);
client.print(String("GET ") + url + " HTTP/1.1\r\n" +
"Host: " + host + "\r\n" +
"User-Agent: BuildFailureDetectorESP8266\r\n" +
"Connection: close\r\n\r\n");
Serial.println("request sent");
while (client.connected()) {
String line = client.readStringUntil('\n');
if (line == "\r") {
Serial.println("headers received");
break;
}
}
String line = client.readStringUntil('\n');
if (line.startsWith("{\"state\":\"success\"")) {
Serial.println("esp8266/Arduino CI successfull!");
} else {
Serial.println("esp8266/Arduino CI has Failed");
}
Serial.println("reply was:");
Serial.println("==========");
Serial.println(line);
Serial.println("==========");
Serial.println("closing connection");
}
void loop() {
}
解决方法
暂无找到可以解决该程序问题的有效方法,小编努力寻找整理中!
如果你已经找到好的解决方法,欢迎将解决方案带上本链接一起发送给小编。
小编邮箱:dio#foxmail.com (将#修改为@)