在Powershell中查找并替换JSON中某个值的所有实例

问题描述

我有一个较大的JSON，其值需要替换为其他值。基本上，我试图在Powershell中查找并替换所有内容。我想删除我们看到的从岩石到岩石的任何地方

JSON

{
  "Customer": [
    {
      "id": "123"
    }
  ],"Nationality": [
    {
      "name": "US","id": "456"
    }
  ],"address": [
    {
      "$type": "Home","name": "Houston","streets": [
        {
          "name": "Union","postalCode": "10",}
      ]
    },{
      "$type": "Office","name": "Hawai","streets": [
        {
          "name": "Rock","postalCode": "11",{
      "$type": "Office1","name": "Hawaii","streets": [
        {
          "name": "Rock 678",{
      "$type": "Office2","name": "Hawai2",}
      ]
    }
    
  ]
}

我正在将JSON更改为对象，但不确定如何找到和替换所有对象。我想删除我们看到的从岩石到岩石的任何地方

代码

$FileContent = Get-Content -Path "Test.json" -Raw | ConvertFrom-Json
$FileContent.address.streets.name = 'Rocky' // I want to do for all the instances.

$FileContent | ConvertTo-Json -Depth 100 | Out-File "Test.json" -Force

解决方法

如何使用Powershell替换文件中的字符串值？

• 用“ Rocky”替换“ Rock”；

• 文件中的设置内容。

  (Get-Content -path C:\Users\Username\Folder\File.json -Raw) -replace 'Rock','Rocky' | Set-Content -path C:\Users\Username\Folder\File.json;