类型'int'不是类型转换json中类型'String'的子类型解码问题

编程问答 2022-06-11

问题描述

我想解码大型JSON，但出现此错误。”（类型'int'不是强制类型转换中'String'类型的子类型）

返回应如下所示： 'IdJB'=> 2，'titel'=>“ lalalala”，'datum'=> 12052003等...

这是我的代码。

Future<Map<String,dynamic>> lol() async {
  final response = await http.post(
      "http://www.bumsbirne.de/2/cool.lol.PHP",body: {
    "status": "1","nam_ersteller": "Quyre","nummer": 1,});
  var data = jsonDecode(response.body);
  
  print(data);
  return data;
}
lol();

多数民众赞成在控制台上

Launching lib/main.dart on iPhone SE (2nd generation) in debug mode...
Running Xcode build...
Xcode build done.                                           13,8s
Waiting for iPhone SE (2nd generation) to report its views...
Debug service listening on ws://127.0.0.1:65295/IdBP__sdzf0=/ws
Syncing files to device iPhone SE (2nd generation)...
[VERBOSE-2:ui_dart_state.cc(171)] Unhandled Exception: type 'int' is not a     subtype of type 'String' in type cast
#0      CastMap.forEach.<anonymous closure>     (dart:_internal/cast.dart:288:25)
#1      _LinkedHashMapMixin.forEach (dart:collection-    patch/compact_hash.dart:377:8)
#2      CastMap.forEach (dart:_internal/cast.dart:287:13)
#3      mapToQuery (package:http/src/utils.dart:17:7)
#4      Request.bodyFields= (package:http/src/request.dart:137:12)
#5      BaseClient._sendUnstreamed (package:http/src/base_client.dart:85:17)
#6      BaseClient.post (package:http/src/base_client.dart:32:7)
#7      post.<anonymous closure> (package:http/http.dart:70:16)
#8      _withClient (package:http/http.dart:166:20)
#9      post (package:http/http.dart:69:5)
#10     _MyHomePageState.initState.lol (package:netzwerk/main.dart:36:30)
#11     _MyHomePageState.initState (package:netzwerk/main.dart:47:8)
#12     StatefulElement._firstBuild         (package:Flutter/src/widgets/framework.dart:4702:58)
#13     ComponentElement.mou<…>

感谢您的帮助

解决方法

您正在将字符串解析为Int。尝试按照下面的代码。只需将所有数据转换为字符串即可。

Future<Map<String,dynamic>> lol() async {
  final response =
      await http.post("http://www.bumsbirne.de/2/cool.lol.php",body: {
    "status": 1.toString(),"nam_ersteller": "Quyre".toString(),"nummer": 1.toString(),});
  var data = jsonDecode(response.body);

  print(data);
  return data;
}
dartdecodedecodehttphttpjson