两张桌子上的累积余额

问题描述

我想从2个表中获取数据，并按日期对它们进行排序： 获取客户的累计余额

我要从中获取数据的2个表是我的表：转账和转帐付款

转移：

ID        int   
cust_id   int   
tfrom     nvarchar(200) 
tto       nvarchar(200)
price     decimal(18,2)
tax       decimal(18,2)
final     Calculated 
tnumber   nvarchar(30)
note      nvarchar(MAX)
date      date

交易付款：

ID       int
cust_id  int
value    decimal(18,2)
method   nvarchar(30)
note     nvarchar(MAX)
date     date

假设我有此数据：

转移：

ID    cust_id   final       date    
1      5        3000     22-09-2020  
2      5        1500     25-09-2020 
3      10       4000     28-09-2020

交易付款：

ID    cust_id   value       date  
1      5        1000     22-09-2020
2      5        1500     23-09-2020
3      5        1000     01-10-2020
4      10       1000     28-09-2020
5      10       2000     01-10-2020

我想创建一个视图以显示客户对购买和付款的操作，如下所示：

客户5：

cust_id   final    value    Balance    date      
5        3000        0       3000     22-09-2020 --- > Purchases 
5         0        1000      2000     22-09-2020 --- > payment
5         0        1500      500      23-09-2020 --- > payment
5        1500        0       2000     25-09-2020 --- > P
5         0        1000      1000     23-09-2020 --- > payment purchases  

最后一行是客户的最终余额

我尝试过：

CREATE VIEW customer_account_summary as 
WITH Tb0 as
( SELECT ID,date,cust_id,final,0'value' from transfers
        UNION
        SELECT ID,0'final',value from trans_payments
),Tb1 as
( 
    SELECT ID,value,Row_Number() over (order by date asc) as [OrderId]
        FROM    
            Tb0
)

SELECT TOP 1000000 T1.ID,T1.cust_id,T1.date,T1.final,T1.value,(Sum(T2.final) - Sum(T2.value)) as Balance FROM Tb1 as T1
            INNER JOIN
                Tb1 as T2
                ON T1.[OrderId] <= T2.[OrderId]
                Group By T1.ID,T1.value
                Order by [date] 

但是我有一个问题，如果2个客户在同一日期付款，那么付款将为2个在同一日期付款的客户计算，我试图添加2个客户的ID以防止查询对数据进行分组，但是我我仍然面临着天平上的错误。

我该如何以正确的方式做到这一点？

解决方法

我认为这是union all和一个窗口sum()：

select cust_id,final,value,date,sum(balance) over(partition by cust_id order by date,seq) balance
from (
        select cust_id,final balance,0 from transfers
        union all
        select cust_id,-value,1 from trans_payments
) t (cust_id,balance,seq)
order by cust_id,seq

当两个表中都存在给定日期的行时，这会将转账放在首位。

Demo on DB Fiddle ：

cust_id | final | value | date       | balance
------: | ----: | ----: | :--------- | ------:
      5 |  3000 |     0 | 2020-09-22 |    3000
      5 |     0 |  1000 | 2020-09-22 |    2000
      5 |     0 |  1500 | 2020-09-23 |     500
      5 |  1500 |     0 | 2020-09-25 |    2000
      5 |     0 |  1000 | 2020-10-01 |    1000
     10 |     0 |  2000 | 2020-01-01 |   -2000
     10 |  4000 |     0 | 2020-09-28 |    2000
     10 |     0 |  1000 | 2020-09-28 |    1000

您可以使用where子句来过滤给定的客户。