如何在强制使用“新”构造函数的同时使结构的所有字段公开可读

问题描述

许多结构需要强制使用构造函数来创建对象，但是我想对所有字段都具有公共读取权限。

由于可读性和可能的​​性能原因，我需要深入了解FirebaseAuth.User的多个级别-select d.name as department,f.name as father,sum_print as sum from department d left join department f on f.id = d.father left join ( select department,sum(page*copy) as sum_print from print where date between CAST('2020-1-13' AS DATE) AND CAST('2020-1-15' AS DATE) group by department ) as tmp on tmp.department = d.id UNION select d.name as department,sum_print as sum from department d left join department f on f.id = d.father right join ( select department,sum(page*copy) as sum_print from print where date between CAST('2020-1-13' AS DATE) AND CAST('2020-1-15' AS DATE) group by department ) as tmp on tmp.department = d.id; 不是我想去的地方。

这个可怕的恶棍是我正在使用的：

bish.bash.bosh.wibble.wobble

这显然浪费了少量空间，bish.get_bash().get_bosh().get_wibble().get_wobble()在其他地方造成了不便。

我应该怎么做？

解决方法

由于@hellow，我现在有了一个可行的解决方案：

use serde::{Serialize,Deserialize}; // 1.0.115

#[derive(Serialize,Deserialize,Debug)]
pub struct Foo {
    pub bar: u8,pub baz: u16,#[serde(skip)] 
    _private: (),}

impl Foo {
    pub fn new(bar: u8,baz: u16) -> Foo {
        Foo {bar,baz,_private: ()}
    }
}