如何在不重复的情况下使用forcat重新编码多个值

问题描述

我想使用forcats通过诸如yes =“ bad”,yes =“ 2”,no =“ 3”,no =“ good”的映射来重新编码因子x,但不重复码。 与yes = levels(x)[1:2]no = levels(x)[3:4]类似。

<!-- language-all: lang-r -->


    library(forcats)

    x <- factor(c("bad","2","good","3","good"),levels = c("bad",2,3,"good"))

    fct_recode(x,yes = "bad",yes = "2",no = "3",no = "good")
    #> [1] yes yes yes no  no  no  no  no 
    #> Levels: yes no

    # I don't want to repeat yes and no
    levels(x)[1:2] # should be yes
    #> [1] "bad" "2"
    levels(x)[3:4] # should be no
    #> [1] "3"    "good"

reprex package(v0.3.0)于2020-10-03创建

解决方法

您可以使用-std=c++20 -Wall -pthread -stdlib=libc++

arg_t()
awaiter_t()
await_ready()
await_suspend()
await_resume()
~awaiter_t()
~arg_t() -> destroyed after the awaiter is destroyed

相关问答

Selenium Web驱动程序和Java。元素在(x,y)点处不可单击。其...
Python-如何使用点“。” 访问字典成员?
Java 字符串是不可变的。到底是什么意思?
Java中的“ final”关键字如何工作?(我仍然可以修改对象。...
“loop:”在Java代码中。这是什么,为什么要编译?
java.lang.ClassNotFoundException:sun.jdbc.odbc.JdbcOdbc...