在python中另一个文件的行中查找模式

问题描述

我正在学习python，所以我有两个行很多的文件：

文件1

71528
1452
14587

文件2

country_hoj_17458   9  CA   5    CA 78.4
country_hoj_1452   10  CA   15   CA 96.5
country_hoj_14787  19  CA   51   CA 12.4
country_hoj_15742  19  CA   51   CA 12.4
country_hoj_171528  19  CA   51   CA 12.4

我想在第一列中打印出模式（编号）文件1与文件2匹配的行。我想要这样的文件

 country_hoj_1452   10  CA   15   CA 96.5
 country_hoj_14787  19  CA   51   CA 12.4

我的脚本是这样的：

filename = numbers.txt
filename2 = data.txt
with open(filename) as f:
    with open (filename2) as m:
        for line in f:
                if line in m:
                       print (m)
     

我需要解决的问题？有人可以帮助我并支持我吗？非常感谢

解决方法

filename = 'numbers.txt'
filename2 = 'data.txt'

with open(filename) as numberLines:
    with open (filename2) as dataLines:
        nL = numberLines.read().splitlines()
        dL = dataLines.read().splitlines()
        dataReadLines = [j for i in nL for j in dL if i in j]
        #dataReadLines = [i for i in nL]
        print (str(dataReadLines))

另一个答案，其中每个键都与各自的数据配对。我更改了您的输入，使用以下代码即可轻松理解。

from collections import defaultdict

filename = 'numbers.txt'
filename2 = 'data.txt'

with open(filename) as numberLines:
    with open (filename2) as dataLines:
        nL = numberLines.read().splitlines()
        dL = dataLines.read().splitlines()
        defDList = defaultdict(list)
        dataReadLines = [defDList[i].append(j) for i in nL for j in dL if i in j]
        #dataReadLines = [i for i in nL]
        print (defDList)