问题描述
我有一幅在透明图像中包含多个rois //非矩形//的图像。.plz帮助我如何将这些rois提取为独立的roi图像
解决方法
- 找到图像的
contours
。
import cv2
img = cv2.imread("gzgSI.jpg")
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
ret,thresh = cv2.threshold(gray,127,255,0)
contours,hierarchy = cv2.findContours(thresh,cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE)
for cnt in contours:
cv2.drawContours(img,[cnt],(0,0),3)
结果:
-
现在确定,我们已经检测到图像中的所有轮廓,可以分别保存它们。
- 在运行代码之前,请确保已创建
rois
文件夹。
代码:
import cv2
img = cv2.imread("gzgSI.jpg")
gray = cv2.cvtColor(img,cv2.CHAIN_APPROX_SIMPLE)
for i,height = cv2.boundingRect(cnt)
roi = img[y:y+height,x:x+width]
cv2.imwrite("rois/roi{}.png".format(i),roi)
,
import numpy as np
import matplotlib.pyplot as plt
!mkdir /content/test
!rm -r /content/test/*
image = cv2.imread('/content/test.png')
original = image.copy()
gray = cv2.cvtColor(image,cv2.COLOR_BGR2GRAY)
blurred = cv2.GaussianBlur(gray,(3,3),0)
canny = cv2.Canny(blurred,120,1)
kernel = np.ones((5,5),np.uint8)
dilate = cv2.dilate(canny,kernel,iterations=1)
# Find contours
cnts = cv2.findContours(dilate,cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if len(cnts) == 2 else cnts[1]
# Iterate thorugh contours and filter for ROI
image_number = 0
for c in cnts:
x,w,h = cv2.boundingRect(c)
#cv2.rectangle(image,(x,y),(x + w,y + h),(36,12),2)
ROI = original[y:y+h,x:x+w]
#cv2.imwrite("/content/test/ROI_{}.png".format(image_number),ROI)
image_number += 1
## (4) Create mask and do bitwise-op
mask = np.zeros(image.shape[:2],np.uint8)
cv2.drawContours(mask,[c],-1,-1)
dst = cv2.bitwise_and(image,image,mask=mask)
## Save it
#cv2.imwrite("dst.png",dst)
cv2.imwrite("/content/test/ROI_{}.png".format(image_number),dst)
image_number += 1
# cv2.imshow('canny',canny)
# cv2.imshow('image',image)
# cv2.waitKey(0)
plt.imshow(canny)
plt.imshow(image)here