问题描述
<?xml version='1.0' encoding='utf-8'?>
<UnlimitRectCubes>
<RectCubes>
<depth>0</depth>
<rectangle>
<height>0</height>
<width>0</width>
</rectangle>
</RectCubes>
<RectCubes>
<depth>1</depth>
<rectangle>
<height>11</height>
<width>101</width>
</rectangle>
</RectCubes>
<RectCubes>
<depth>2</depth>
<rectangle>
<height>22</height>
<width>202</width>
</rectangle>
</RectCubes>
</UnlimitRectCubes>
void print_element_names(xmlNode *a_node,char **findStr)
{
xmlNode *cur_node = NULL;
char *key = *findStr;
cur_node = a_node;
int len = 0;
while (cur_node)
{
if ((!xmlStrcmp(cur_node->name,(const xmlChar *)key)))
{
len++; //len is int type
}
cur_node = cur_node->next;
}
printf("%d",len);
//int i = 0;
//xmlChar *array = (xmlChar *)calloc(1,sizeof(xmlChar));
for (cur_node = a_node; cur_node; cur_node = cur_node->next)
{
if ((cur_node->type == XML_ELEMENT_NODE))
{
if ((!xmlStrcmp(cur_node->name,(const xmlChar *)key)))
{
//printf("%s",cur_node->children->content);
}
}
print_element_names(cur_node->children,findStr);
}
}
int main(int argc,char **argv)
{
xmlDoc *doc = NULL; /* an xml document */
xmlNode *root_element = NULL; /* a node in a xml tree */
if (argc != 2)
{
return (1);
}
LIBXML_TEST_VERSION
/* parse the file and get the DOM */
doc = xmlReadFile(argv[1],NULL,0);
if (doc == NULL)
{
printf("error Could not parse");
return;
}
/*Get the root element*/
root_element = xmlDocgetRootElement(doc);
char *myStr = "depth";
print_element_names(root_element,&myStr);
xmlFreeDoc(doc);
/*
*free the global variables that may have been allocated by the parser
*/
xmlCleanupParser();
return 0;
}
输出:0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
我需要找到.xml文件中特定标签的出现频率,在这里我已将其作为键(char *)传递给函数,并使用xmlStrCmp()来验证正确的标签。
该len应该打印整数值,但似乎输出以下内容:请参考上面的输出。实际出现3个特定标签,并且输出show具有3个1。 我相信,我没有正确地遍历XML树,正确的方法是什么?还是有任何XML函数可实现这一目标?
输入:.xml文件和感兴趣的标记作为键传递 预期输出:标签出现的次数,在这种情况下,我应该得到3。
for (cur_node = a_node; cur_node; cur_node = cur_node->next)
{
if ((cur_node->type == XML_ELEMENT_NODE))
{
if ((!xmlStrcmp(cur_node->children->name,(const xmlChar *)key)))
{
//printf("%s\n",cur_node->children->content);
}
printf("%s",cur_node->name);
}
len += print_element_names(cur_node->children,findStr);
}
printf("%d ",len);
更新的输出: UnlimitRectCubes0 RectCubes0深度0 2 0矩形0高度0 2 0宽度0 2 0 10 0 11 0 RectCubes0深度0 2 0矩形0高度0 2 0宽度0 2 0 10 0 11 0 RectCubes0深度0 2 0矩形0高度0 2 0宽度0 2 0 10 0 11 0 17 3 >
解决方法
您不会将找到的标签的数量在一个级别上传播到呼叫级别。
我尝试了这段代码并获得了正确的结果:
/*
* Compile with:
* > gcc `xml2-config --cflags` -std=c99 -o test test.c `xml2-config --libs`
* */
#include <stdio.h>
#include <stdlib.h>
#include <libxml/parser.h>
#include <libxml/tree.h>
int print_element_names(xmlNode *a_node,char **findStr)
{
xmlNode *cur_node = a_node;
char *key = *findStr;
int len = 0;
if (a_node == NULL)
return 0;
printf("a_node->name=%s\n",a_node->name);
while (cur_node)
{
printf("cur_node->name=%s,type=%d\n",cur_node->name,cur_node->type);
if ((!xmlStrcmp(cur_node->name,(const xmlChar *)key)))
{
len++; //len is int type
}
cur_node = cur_node->next;
}
printf("found=%d\n",len);
for (cur_node = a_node; cur_node; cur_node = cur_node->next)
{
if ((cur_node->type == XML_ELEMENT_NODE))
{
printf("search children for cur_node->name=%s,cur_node->type);
len += print_element_names(cur_node->children,findStr);
}
}
printf("found total for a_node->name %s: %d\n",a_node->name,len);
return len;
}
int main(int argc,char **argv)
{
xmlDoc *doc = NULL; /* an xml document */
xmlNode *root_element = NULL; /* a node in a xml tree */
LIBXML_TEST_VERSION
/* parse the file and get the DOM */
doc = xmlReadFile("test.xml",NULL,0);
if (doc == NULL)
{
printf("error could not parse");
return 1;
}
/*Get the root element*/
root_element = xmlDocGetRootElement(doc);
char *myStr = "depth";
print_element_names(root_element,&myStr);
xmlFreeDoc(doc);
xmlCleanupParser();
return 0;
}