问题描述
我有一些饭食json,我想将其转换为MealData
结构
let randomMealJson = """
{
"meals": [{
"idMeal": "52812","strMeal": "Beef Brisket Pot Roast","strDrinkAlternate": null,"strCategory": "Beef","strArea": "American","strInstructions": "Meal instructions","strMealThumb": "https://www.themealdb.com/images/media/meals/ursuup1487348423.jpg","strTags": "Meat","strYoutube": "https://www.youtube.com/watch?v=gh48wM6bPWQ","strIngredient1": "Beef Brisket","strIngredient2": "Salt","strIngredient3": "Onion","strIngredient4": "Garlic","strIngredient5": "Thyme","strIngredient6": "Rosemary","strIngredient7": "Bay Leaves","strIngredient8": "beef stock","strIngredient9": "Carrots","strIngredient10": "Mustard","strIngredient11": "Potatoes","strIngredient12": null,"strIngredient13": null,"strIngredient14": null,"strIngredient15": null,"strIngredient16": null,"strIngredient17": null,"strIngredient18": null,"strIngredient19": null,"strIngredient20": null,"strMeasure1": "4-5 pound","strMeasure2": "Dash","strMeasure3": "3","strMeasure4": "5 cloves","strMeasure5": "1 Sprig","strMeasure6": "1 sprig ","strMeasure7": "4","strMeasure8": "2 cups","strMeasure9": "3 Large","strMeasure10": "1 Tbsp","strMeasure11": "4 Mashed","strMeasure12": "","strMeasure13": "","strMeasure14": "","strMeasure15": "","strMeasure16": "","strMeasure17": "","strMeasure18": "","strMeasure19": "","strMeasure20": "","strSource": "http://www.simplyrecipes.com/recipes/beef_brisket_pot_roast/","dateModified": null
}]
}
"""
这是我要制作的结构...
struct MealData: Decodable {
let meals: [Meal]
}
struct Meal: Decodable {
let items: [Item]
}
extension Meal {
struct Item: Decodable {
let ingredient: String
let measure: String
}
}
extension Meal {
init(from decoder: Decoder) throws {
// var items: [Item] = (0...20).map { num in
// what to do here?
// }
}
}
我想仔细研究一下这些要素和措施,并根据它们创建一个Meal.Item
,但是我不知道如何实现这一目标。我在代码中指出的方式有可能吗?
解决方法
我将分两步执行此操作。首先解码成字典
struct MealData: Decodable {
let meals: [[String: String?]]
}
然后我将在单独的步骤中转换为另一种类型
struct Recipie {
var ingredients: [Ingredient]
}
struct Ingredient {
let ingredient: String
let measure: String
}
这是完整的代码
do {
let result = try JSONDecoder().decode(MealData.self,from: randomMealJson)
var recipies = [Recipie]()
for meal in result.meals {
var recipie = Recipie(ingredients: [])
var index = 1
while true {
guard let ingredientValue = meal["strIngredient\(index)"],let measureValue = meal["strMeasure\(index)"],let ingredient = ingredientValue,let measure = measureValue,!measure.isEmpty
else { break }
recipie.ingredients.append(Ingredient(ingredient: ingredient,measure: measure))
recipies.append(recipie)
index += 1
}
}
} catch {
print(error)
}
,
@ joakim-danielson的回答。您可以在init(from:)
初始化程序中执行相同的操作,就像您的初衷一样。
只需将每个Meal
的成分和度量解码为[String: String?]
,然后编写自定义的Item
s:
extension Meal {
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
let mealDict = try container.decode([String: String?].self)
var index = 1
var items = [Item]()
while
let ingredient = mealDict["strIngredient\(index)"] as? String,let measure = mealDict["strMeasure\(index)"] as? String,!measure.isEmpty
{
items.append(Item(ingredient: ingredient,measure: measure))
index += 1
}
self.items = items
}
}