清除反斜杠中的字符串，并将结果放入数据结构中

问题描述

我有这个字符串

clean()

如何从该字符串中清除反斜杠并将实体放入数据结构中？

解决方法

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

import org.json.JSONArray;
import org.json.JSONException;

import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;

public class SOTest {

    public static void main(String[] args) throws JsonMappingException,JsonProcessingException,JSONException {
        ObjectMapper mapper = new ObjectMapper();
        String jsonString = "[{\"name\":\"john\",\"family\":[],\"status\":\"single\"},{\"name\":\"david\",\"status\":\"marred\"}]";
        List<CustomClass> datas = mapper.readValue(jsonString,new TypeReference<List<CustomClass>>() {});
        System.out.println(datas);
    }
}

class CustomClass {
    public String name;
    public List<CustomClass> family;
    public String status;

    @Override
    public String toString() {
        return "Data [name=" + name + ",family=" + family + ",status=" + status + "]";
    }
}

输出

[Data [name=john,family=[],status=single],Data [name=david,status=marred]]

,

该字符串看起来还可以。转义已完成，以在Java中使用字符串。

使用Jackson之类的库。为您的任务。

• Complete read/write example

• Example on how to read json to a map

• Example on how to read json to a JsonNode

,

用jshell控制台编写，因此您需要根据需要添加类等

import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.databind.ObjectMapper;

import java.io.IOException;

try {
    String json = "[{\"name\":\"john\",\"status\":\"marred\"}]";
    json = json.replace("\\\"","\"");
    System.out.println(json);

    ObjectMapper mapper = new ObjectMapper();
    Person[] persons = mapper.readValue(json,Person[].class);
    System.out.println(persons[0].name);
} catch (IOException e) {
    e.printStackTrace();
}

static class Person {

    public final String name;
    public final String[] family;
    public final String status;

    @JsonCreator
    public Person(
            @JsonProperty("name") String name,@JsonProperty("family") String[] family,@JsonProperty("status") String status
    ) {
        this.name = name;
        this.family = family;
        this.status = status;
    }
}