Caliburn.Micro-将组合框项目传递给按钮

问题描述

我正在尝试将组合框（绑定到我的Model对象的列表）中的项目传递给我的按钮。我的问题是我是Caliburn.Micro + WPF的新手，并且不确定如何向按钮订阅/传递所需的值（例如，将PropetyName的字符串发送到Button（字符串propetyName））。

viewmodel代码：

dictionary = {'Links':links,'Skills':skills}

df = pd.DataFrame(dictionary)

print(df)

XAML代码：

                                                                                                           
                Skills                                                   Links
0  https://www.livecareer.com//resume-search/r/so...  agile,AutoCAD,C++,CAD,Oral,data entry,da...
1  https://www.livecareer.com//resume-search/r/so...  Senior Outreach at Senior Center Planned and o...
2  https://www.livecareer.com//resume-search/r/so...  Motivated Software Engineer seeking employment...
3  https://www.livecareer.com//resume-search/r/so...  Developed peer-to-peer secure file transfer sy...
4  https://www.livecareer.com//resume-search/r/so...  Performance evaluation of In-Kernel System Cal...
5  https://www.livecareer.com//resume-search/r/so...  Accomplished Computer Technician with a rapidl...
6  https://www.livecareer.com//resume-search/r/so...  Seeking a fulltime position as a Developer / S...
7  https://www.livecareer.com//resume-search/r/so...  3 Years of experience in information Technolog...
8  https://www.livecareer.com//resume-search/r/so...  .NET 3.5,.NET,ASP .NET 3.5,ASP.NET 2.0,ASP...
9  https://www.livecareer.com//resume-search/r/so...  Represent Stanford  Ballroom Dance team in var...

很抱歉，如果我的描述含糊/缺少更多说明，我是这里的新用户！

解决方法

FileInFolder是组合中的选定项。

OpenFile位于同一类中，因此可以引用FileInFolder。

public void OpenFile()
{
     var whatever = FileInFolder.SomeProperty;
   // etc
}

您可能想要在其中进行null检查。