如何检测“长按”

问题描述

我有一个UIView视图,我想在用户按下然后释放时执行一些操作。 我在视图中添加UITapGestureRecognizer,并且只有在点击持续时间较小时才会触发。如果用户触摸该视图,等待几秒钟然后举起手指,则什么也没有发生。如何检测“长按”事件?

UILongPressGestureRecognizer对我不起作用,因为当手指仍然触摸屏幕时它将触发。

解决方法

您可以通过跟踪touchesBegantouchesEnded的时间来做到这一点:

class LongTapView: UIView {
    
    var touchStart: Date!
    
    var callback: ((Double)->())?
    
    override func touchesBegan(_ touches: Set<UITouch>,with event: UIEvent?) {
        touchStart = Date()
    }
    override func touchesMoved(_ touches: Set<UITouch>,with event: UIEvent?) {
        guard let touchPoint = touches.first?.location(in: self),self.bounds.contains(touchPoint) else {
            // touch moved outside of self,//  so don't consider it "still pressed"
            touchStart = Date.distantFuture
            return
        }
    }
    override func touchesEnded(_ touches: Set<UITouch>,self.bounds.contains(touchPoint) else {
            // touch was lifted outside of self
            return
        }
        let seconds = -(touchStart.timeIntervalSinceNow)
        if seconds < 0.0 {
            // this will be the case if touchesMoved outside of self
            //  and then was dragged back in
            return
        }
        // tell the controller how long the view was touched
        callback?(seconds)
    }
}

您可以像这样使用它:

class TouchTestViewController: UIViewController {
    
    override func viewDidLoad() {
        super.viewDidLoad()
        
        let v = LongTapView()
        v.frame = CGRect(x: 80,y: 120,width: 150,height: 150)
        v.backgroundColor = .red
        view.addSubview(v)
        
        v.callback = { elapsedTime in
            // do what you want here,for example:
            if elapsedTime > 4.0 {
                print("View was pressed longer than 4 seconds!")
            } else {
                print("View was pressed for only \(elapsedTime) seconds")
            }
        }
        
    }
}