SQL中基于总和的最高价值维度

问题描述

我在查询每个位置的顶级交易类型时遇到问题：

我的表的位置为varchar，类型为varchar，事务为int

我尝试了以下操作并收到错误消息：

select  
c.location,c.type,sum(c.transaction) as trans_sum
from sales c
group by c.location,c.type
having trans_sum = (
select top 1
c2.type,sum(c2.transaction) as trans_sum2
from sales c2
where c2.location = c.location
group by c2.location,c2.type
order by c2.location,trans_sum2 desc
)
order by c.location,trans_sum desc;

基本上，我想要每种类型和位置的交易列的最高汇总值。

Location Type    Noun
--------------------- 
Atlanta  Channel 750 
Atlanta  Direct  2250 
Atlanta  CC      1850 
Chicago  Channel 625 
Chicago  Direct  1125 
Chicago  CC      612
Dallas   Channel 2183
Dallas   Direct  1165
Dallas   CC      965

...................................... 我正在寻找的结果是： ................................

    Location Type    Noun
    ---------------------  
    Atlanta  Direct  2250 
    Chicago  Direct  1125
    Dallas   Channel 2183

...................................

因此，返回的sql列表的顶部位置并键入汇总值。我还要每个位置/类型配对的前3个值

解决方法

删除您选择的c2.type

select  
c.location,c.type,sum(c.transaction) as trans_sum
from sales c
group by c.location,c.type
having trans_sum = (
select top 1
sum(c2.transaction) as trans_sum2
from sales c2
where c2.location = c.location
group by c2.location,c2.type
order by c2.location,trans_sum2 desc
)
order by c.location,trans_sum desc;

,

您可能使用sql-server !？如果是这样，我在使用名称“ transaction”作为列时遇到了第一个错误。该名称已被sql server使用，因此我对其进行了更改。

第二，我认为您不能在Have语句中使用别名“ trans_sum”。改为使用sum（c.trans）。

这应该有效：

select  
       c.location,sum(c.trans) as trans_sum
 from  foobar c
group by c.location,c.type
having sum(c.trans) = (
         select top 1
                sum(c2.trans) as trans_sum2
           from foobar c2
          where c2.location = c.location
          group by c2.location,c2.type
          order by c2.location,trans_sum2 desc
        )
order by c.location,trans_sum desc;