Hibernate SQL @JoinColumn生成null

问题描述

我正在使用@JoinColumn Annotation来联接两个表，但是链接结果为空值。我究竟做错了什么？有什么方法可以调试链接过程？也许与sql数据库有关，我的意思是没有链接可以发生？您可能会说我在代码方面已经尝试了所有方法，所以我不确定代码是否可能是问题。我也使用Postman发送JSON字符串，也许问题出在那，但这只是猜测。请帮忙。

@Entity
@Data
public class Operator {


    @Id
    @GeneratedValue
    private int idOperator;

    @Column
    private String login;

    @Column
    private String password;


    @OneToOne(fetch = FetchType.EAGER,cascade = CascadeType.ALL)
    @JoinColumn(name= "id_employee")
    private Employee employee;

@Entity
@Data
public class Employee {

    @Id
    @GeneratedValue
    private int id_employee;

    @Column
    private String firstName;

    @Column
    private String lastName;

    @OneToOne(mappedBy = "employee")
    private Operator operator;
    
}


@RestController
@RequiredArgsConstructor
public class EmployeeController {

    private final EmployeeRepository employeeRepository;


    @PostMapping("/employees")
    public Employee newEmployee(@RequestBody Employee newEmployee) {
        return employeeRepository.save(newEmployee);
    }


@RestController
@RequiredArgsConstructor
public class OperatorController {

    private final OperatorRepositry operatorRepositry;


    @PostMapping("/operators")
    public Operator newOperator(@RequestBody Operator newOperator) {
        return operatorRepositry.save(newOperator);
    }


The debug result: 

    2020-10-12 11:40:19.467 DEBUG 83385 --- [nio-8080-exec-2] org.hibernate.SQL                        : insert into operator (id_employee,login,password,id_operator) values (?,?,?)
    2020-10-12 11:40:19.470 TRACE 83385 --- [nio-8080-exec-2] o.h.type.descriptor.sql.BasicBinder      : binding parameter [1] as [INTEGER] - [null]
    2020-10-12 11:40:19.471 TRACE 83385 --- [nio-8080-exec-2] o.h.type.descriptor.sql.BasicBinder      : binding parameter [2] as [VARCHAR] - [dbuser]
    2020-10-12 11:40:19.472 TRACE 83385 --- [nio-8080-exec-2] o.h.type.descriptor.sql.BasicBinder      : binding parameter [3] as [VARCHAR] - [skdbpassword]
    2020-10-12 11:40:19.472 TRACE 83385 --- [nio-8080-exec-2] o.h.type.descriptor.sql.BasicBinder      : binding parameter [4] as [INTEGER] - [7]
    select operator0_.id_operator as id_opera1_1_1_,operator0_.id_employee as id_emplo4_1_1_,operator0_.login as login2_1_1_,operator0_.password as password3_1_1_,employee1_.id_employee as id_emplo1_0_0_,employee1_.first_name as first_na2_0_0_,employee1_.last_name as last_nam3_0_0_ from operator operator0_ left outer join employee employee1_ on operator0_.id_employee=employee1_.id_employee where operator0_.id_operator=?

解决方法

暂无找到可以解决该程序问题的有效方法，小编努力寻找整理中！

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