问题描述
在Django Rest Framework中创建id
后,我想获得新的Post
作为响应。
预期功能:用户会收到一个JSON响应,其中包含指向创建的新项目的超链接。
POST
{
"label": "BMW M3","price": 5000.00
}
响应:
{
"id-url": "www.website.com/api/products/id/"
}
我知道这个主题已经以各种方式涉及到了,但是我正在寻找使用ModelSerializer的最小(但完整)示例,我还无法找到它,因此是我的问题。
我的模特:
class Product(models.Model):
label = models.CharField(max_length=50,blank=True,null=True)
price = models.FloatField(blank=True,null=True)
我的序列化器:
class ProductSerializer(serializers.ModelSerializer):
class Meta:
model = Product
fields = '__all__'
我的观点:
class ProductViewSet(viewsets.ModelViewSet):
queryset = Product.objects.all()
serializer_class = ProductSerializer
我的网址:
router = routers.DefaultRouter()
router.register('products',ProductViewSet)
urlpatterns = [
path('',include(router.urls)),]
尝试:
我尝试了一些参考。 这是一个类似的问题,但答案确实不完整ex_0 我可以重新创建此ex_1,但没有给我ID
解决方法
感谢这篇文章:Get the id of the object recently created Django Rest Framework我设法提出了一个潜在的解决方案。这似乎可行,但我不确定这是否是“最佳”方法。
class ProductViewSet(viewsets.ModelViewSet):
queryset = Product.objects.all()
serializer_class = ProductSerializer
def create(self,request):
serializer = ProductSerializer(data=request.data)
if serializer.is_valid():
product = serializer.save()
pid = product.id
product.url = f'http://localhost:8000/api/products/{pid}/'
data = serializer.data
data.update({'id-url':product.url}) # attaching key-value to the dictionary
return Response(data,status=status.HTTP_201_CREATED)
else:
return Response(serializer.errors,status=status.HTTP_400_BAD_REQUEST)
,
class ProductViewSet(viewsets.ModelViewSet):
queryset = Product.objects.all()
serializer_class = ProductSerializer
def create(self,request,*args,**kwargs):
response = super(ProductViewSet,self).create(request,**kwargs)
# response.data has everything specified in your serializer; it seems fine to clobber it
# alternatively,you could add to it: response.data['foo']='baz'
response.data = {'id-url': f'http://localhost:8000/api/products/{response.data['id']}/'}
return response