使用SQL在Woocommerce中获取具有特定属性术语和特定类别术语的产品

编程问答 2022-06-09

问题描述

我希望找到具有两种不同标准的产品。

我首先用于搜索一个条件的代码是; 

SELECT rel.object_id,rel.term_taxonomy_id,tt.taxonomy,tt.term_id,ts.name
FROM df1wrmw_term_taxonomy tt
INNER JOIN df1wrmw_term_relationships rel ON tt.term_taxonomy_id = rel.term_taxonomy_id
INNER JOIN df1wrmw_terms ts ON tt.term_id = ts.term_id
WHERE tt.taxonomy = "pa_1_scale"
AND ts.term_id = 400;

这将返回所有具有属性“ pa_1_scale”和ts.term_id = 400 的乘积（Object_ID）。我还可以执行此操作，以使用其他 WHERE 语句

返回所有 product_cat和ts.term_id = 397 的产品 
WHERE tt.taxonomy = "product_cat"
AND ts.term_id = 397

UNION ALL只是将两者结合在一起。如何让sql选择这两个条件？我知道将这两个条件组合在一起的WHERE语句将不起作用，因为我认为没有表行同时包含这两个值？

任何可用的帮助都会很棒。

解决方法

您可以尝试使用以下方法将重复的表与不同的变量引用连接在一起，从而允许将两个查询合并为一个：

SELECT tr.object_id,tr.term_taxonomy_id,tt.taxonomy,t.term_id,t.name,tr2.term_taxonomy_id as term_taxonomy_id2,tt2.taxonomy as taxonomy2,t2.term_id as term_id2,t2.name as name2
FROM df1wrmw_term_relationships tr
INNER JOIN df1wrmw_term_taxonomy tt
    ON tr.term_taxonomy_id = tt.term_taxonomy_id
INNER JOIN df1wrmw_terms t
    ON tt.term_id = t.term_id
INNER JOIN df1wrmw_term_relationships tr2
    ON tr.object_id = tr2.object_id
INNER JOIN df1wrmw_term_taxonomy tt2
    ON tr2.term_taxonomy_id = tt2.term_taxonomy_id
INNER JOIN df1wrmw_terms t2
    ON tt2.term_id = t2.term_id
WHERE tt.taxonomy = 'pa_1_scale'
    AND t.term_id = 400
    AND tt2.taxonomy = 'product_cat'
    AND t2.term_id = 397

或者您可以在WordPress中使用类WPDB and its methods来获取PHP中的SQL查询结果：

global $wpdb;

$results = $wpdb->get_results("
    SELECT tr.object_id,t2.name as name2
    FROM {$wpdb->prefix}term_relationships tr
    INNER JOIN {$wpdb->prefix}term_taxonomy tt
        ON tr.term_taxonomy_id = tt.term_taxonomy_id
    INNER JOIN {$wpdb->prefix}terms t
        ON tt.term_id = t.term_id
    INNER JOIN {$wpdb->prefix}term_relationships tr2
        ON tr.object_id = tr2.object_id
    INNER JOIN {$wpdb->prefix}term_taxonomy tt2
        ON tr2.term_taxonomy_id = tt2.term_taxonomy_id
    INNER JOIN {$wpdb->prefix}terms t2
        ON tt2.term_id = t2.term_id
    WHERE tt.taxonomy = 'pa_1_scale'
        AND t.term_id = 400
        AND tt2.taxonomy = 'product_cat'
        AND t2.term_id = 397
");

// Display preformatted raw output
echo '<pre>' . print_pr($results,true) . '</pre>';

应该可以。

sqlsqltaxonomy-termswordpresswordpress