问题描述
我的数据在Excel中。我有几张数据，其中地址始终位于每张纸的同一列中。地址格式的示例包括：
华盛顿特区15街15号1155号西北套房20005美国
4600 Emperor Blvd＃200 Durham，NC 27703-8577 US
200 Stevens Drive费城，PA 19113美国
505 City Parkway西奥兰治，CA 92868美国
550 S Caldwell St，夏洛特，NC 28202-2633 US
1643 NW 136th Ave Ste H200 Sunrise，FL 33323-2857 US
我已经尝试过下面的代码，但是此时在代码“ sCity = Trim（Mid $（rCell.Value，Len（sAddress）+ 1，lStatePos-Len（sAddress）-1））”中出现错误。
有人可以帮我弄清楚如何解决此问题吗？
Sub SplitAddresses()
Dim vaStates As Variant
Dim vaStreets As Variant
Dim i As Long
Dim rCell As Range
Dim sAddress As String
Dim sCity As String,sstate As String
Dim sZip As String
Dim lStreetPos As Long,lStatePos As Long
vaStates = Array(“ AL “,“ AK “,“ AZ “,“ AR “,“ CA “,“ CO “,“ CT “,“ DE “,“ DC “,“ FL “,“ GA “,“ HI “,“ ID “,“ IL “,“ IN “,“ IA “,“ KS “,“ KY “,“ LA “,“ ME “,“ MD “,“ MA “,“ MI “,“ MN “,“ MS “,“ MO “,“ MT “,“ NE “,“ NV “,“ NH “,“ NJ “,“ NM “,“ NY “,“ NC “,“ ND “,“ OH “,“ OK “,“ OR “,“ PA “,“ RI “,“ SC “,“ SD “,“ TN “,“ TX “,“ UT “,“ VT “,“ VA “,“ WA “,“ WV “,“ WI “,“ WY “,“ GU “,“ PR “)
vaStreets = Array(" CR "," BLVD "," RD "," ST "," AVE "," CT ")
For Each rCell In Sheet1.Range("A1:A5").Cells
sAddress = "": sCity = "": sZip = "": sstate = ""
For i = LBound(vaStreets) To UBound(vaStreets)
lStreetPos = InStr(1,rCell.Value,vaStreets(i))
If lStreetPos > 0 Then
sAddress = Trim(Left$(rCell.Value,lStreetPos + Len(vaStreets(i)) - 1))
Exit For
End If
Next i
For i = LBound(vaStates) To UBound(vaStates)
lStatePos = InStr(1,vaStates(i))
If lStatePos > 0 Then
sCity = Trim(Mid$(rCell.Value,Len(sAddress) + 1,lStatePos - Len(sAddress) - 1))
sstate = Trim(Mid$(rCell.Value,lStatePos + 1,Len(vaStates(i)) - 1))
sZip = Trim(Mid$(rCell.Value,lStatePos + Len(vaStates(i)),Len(rCell.Value)))
Exit For
End If
Next i
rCell.Offset(0,1).Value = "'" & sAddress
rCell.Offset(0,2).Value = "'" & sCity
rCell.Offset(0,3).Value = "'" & sstate
rCell.Offset(0,4).Value = "'" & sZip
Next rCell
End Sub
这是我得到的错误： error_image
解决方法
拆分逻辑中存在一些不一致之处，这还不包括您必须将大写街道数组也与Ucase()字符串值进行比较。
但是，好消息-由于您似乎采用了随后的地址逻辑，即将城市，州/省/自治区（+）括在最后冒号分隔符周围，因此可以尝试以下代码：
Option Explicit ' declaration head of code module
Enum c ' define column constants
[_Start] = 0
add1
City
State
Zip
End Enum
Sub SplitAddresses()
With Sheet1
'define dataset
Dim lastRow As Long: lastRow = .Range("A" & .Rows.Count).End(xlUp).Row
Dim rng As Range: Set rng = .Range("A2:A" & lastRow)
'assign to variant datafield array (provide for 4 columns: Add+City+State+ZIP)
Dim v: v = rng.Resize(columnsize:=4).Value2
'split data
doSplit v
'write split results to any target,e.g. B:B
.Range("B2").Resize(UBound(v),4) = v
End With
End Sub
帮助过程doSplit
Sub doSplit(data)
Dim i As Long
For i = LBound(data) To UBound(data)
Dim curAddress As String: curAddress = data(i,c.add1)
Dim tokens,tmp
tokens = Split(curAddress,",")
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
'a) analyze string part after last ","
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
tmp = Split(Trim(tokens(UBound(tokens))) & " "," ",2)
'aa) add State + Zip (to columns 3..4)
data(i,c.State) = tmp(0): data(i,c.Zip) = tmp(1)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
'b) analyze first string part
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
tmp = Split(tokens(UBound(tokens) - 1)," ")
'data(i,c.City) = tmp(UBound(tmp)) '<< only for 1-word city names
data(i,c.City) = getCity(tmp) '<< see edit below
'bb) add City + Address
data(i,c.add1) = Split(curAddress,data(i,c.City),2)(0)
data(i,c.add1) = Replace(data(i,c.add1),"")
Next i
End Sub
帮助功能 //由于@RonRosenfeld的评论而进行编辑
由于会有由复合词组成的城市名称，因此必须将上面子区域中的城市字符串分配从data(r,c.City) = tmp(UBound(tmp))更改为
data(r,c.City) = getCity(tmp) ' << function call
功能getCity()
包括对common开头部分的检查，如“北部”，“西部”或“新”，以避免至少检查带有复合城市名称的详尽列表。必须在附加列表cities中定义所有其他需要的具有多个单词的城市名称：
Function getCity(tmp) As String
'Purp.: return valid city names of either one or two parts
'[1]Definitions
'a) List common first parts of city names like "West" in "West Orange"
Dim common$: common = "North,West,South,East,Grand,New"
'b) List all other needed cities consisting of compound words
Dim cities$: cities = "Sterling Heights,Ann Arbor"
'[2]Get potential city name
'a) Define tmp indices of potential city tokens
Dim first&: first = UBound(tmp) - 1
Dim secnd&: secnd = UBound(tmp)
'b) Build city name as compound string of tmp tokens
Dim City As String
City = Trim(IIf(first < 0,"",tmp(first) & " ") & tmp(secnd))
'[3]Check common first parts plus additional cities list
'a) Check for common name parts like e.g. "West" in "West Orange"
If InStr(common & ",tmp(first) & ",") Then getCity = City: Exit Function
'b) Check rest in listed cities and return function result
getCity = IIf(InStr(cities,City) > 0,City,tmp(secnd))
End Function
在您的评论中，有一个返回字符来描述城市的街道地址，以及地址的常规格式：street|City,State Zip Country该算法变得更加简单，因为一系列Split函数可以分开地址部分。
我还使用了Type语句-不必要，但是使代码更清晰，IMO。
根据格式，某些Trim语句可能不是必需的，但它们不会受到损害。
请注意，您可以更改数据源和结果位置的范围/表格以适合您的特定要求。
编辑：我刚读完您的评论，即从街道地址返回市区之前，可能会有多个returns。
.street的代码已相应更改
Option Explicit
Type Address
street As String
city As String
state As String
zip As String
country As String
End Type
Sub splitAddresses()
Dim wsSrc As Worksheet,wsRes As Worksheet,rRes As Range
Dim vSrc As Variant,vRes As Variant
Dim myAdr As Address
Dim v,w,x,y
Dim I As Long
Set wsSrc = Worksheets("sheet1")
'read into vba array for faster processing
With wsSrc
vSrc = .Range(.Cells(2,1),.Cells(.Rows.Count,1).End(xlUp))
End With
Set wsRes = Worksheets("Sheet1")
Set rRes = wsRes.Cells(1,3)
ReDim vRes(0 To UBound(vSrc),1 To 5)
'Headers
vRes(0,1) = "Street"
vRes(0,2) = "City"
vRes(0,3) = "State"
vRes(0,4) = "Zip"
vRes(0,5) = "Country"
For I = 1 To UBound(vSrc)
v = Split(vSrc(I,vbLf)
With myAdr
y = v
ReDim Preserve y(UBound(y) - 1)
.street = WorksheetFunction.Trim(Join(y," "))
w = Split(Trim(v(UBound(v))),")
.city = w(0)
x = Split(Trim(w(1)))
.state = Trim(x(0))
.zip = Trim(x(1))
.country = Trim(x(2))
vRes(I,1) = .street
vRes(I,2) = .city
vRes(I,3) = .state
vRes(I,4) = .zip
vRes(I,5) = .country
End With
Set rRes = rRes.Resize(rowsize:=UBound(vRes,1) + 1,columnsize:=UBound(vRes,2))
With rRes
.EntireColumn.Clear
.Value = vRes
.Rows(1).Font.Bold = True
.Columns(4).NumberFormat = "@"
.EntireColumn.AutoFit
End With
Next I
End Sub
