如何使用python输入更新mysql

问题描述

我正在尝试做一个简单的程序来用作contact_book，但是当我尝试更新行时却无法解决错误。 这是代码：

MysqL.connector.errors.ProgrammingError: 1064 (42000): You have an error in your sql Syntax; check 
the manual that corresponds to your MysqL server version for the right Syntax to use near '''nome'' = 
''Ivone'' WHERE index_num = ''2''' at line 1

将所有输入放到一个变量中，然后再提交给INSERT联系人的相同语法，但是在更新时出现错误：

<template>
  <div class="swiper-container">
      <!-- Additional required wrapper -->
      <div class="swiper-wrapper">
          <!-- Slides -->
          <div class="swiper-slide">Slide 1</div>
          <div class="swiper-slide">Slide 2</div>
          <div class="swiper-slide">Slide 3</div>
          ...
      </div>
      <!-- If we need pagination -->
      <div class="swiper-pagination"></div>

      <!-- If we need navigation buttons -->
      <div class="swiper-button-prev"></div>
      <div class="swiper-button-next"></div>

      <!-- If we need scrollbar -->
      <div class="swiper-scrollbar"></div>
  </div>
</template>

<script>
import Swiper,{ Navigation,Pagination } from 'swiper'
import 'swiper/swiper-bundle.css'

Swiper.use([ Navigation,Pagination ])

export default {
  mounted() {
    new Swiper('.swiper-container',{
      loop: true,pagination: {
        el: '.swiper-pagination',},navigation: {
        nextEl: '.swiper-button-next',prevEl: '.swiper-button-prev',scrollbar: {
        el: '.swiper-scrollbar',})
  }
}
</script>

<style scoped>
.swiper-container {
  width: 600px;
  height: 300px;
}
</style>

解决方法

在执行之前，您需要在查询中提供字段名称：

editar = (para,index,)

然后：

sql = "UPDATE contato SET %s = %%s WHERE index_num = %%s" % (oque)

或

sql = "UPDATE contato SET {} = %s WHERE index_num = %s".format(oque)```

或（python 3.6 +）

sql = f"UPDATE contato SET {oque} = %s WHERE index_num = %s"

然后：

my_cursor.execute(sql,editar)