问题描述
我正在尝试使用openjpa和MysqL来保留单个类,真的没有什么戏剧性。
Attempt to cast instance "xxx" to PersistenceCapable Failed. Ensure that it has been enhanced.
所以我环顾四周,发现了这个 https://openjpa.apache.org/builds/2.2.1/apache-openjpa/docs/ref_guide_pc_enhance.html 他们建议使用
java -javaagent:/home/dev/openjpa/lib/openjpa.jar com.xyz.Main
现在,我将其添加到我的intellij运行时配置中的VM-Options中:
-javaagent:/home/xxx/Downloads/apache-openjpa-3.1.2/openjpa-all-3.1.2.jar main.java.entity.Post
但是它似乎无法识别该类:
You have enabled runtime enhancement,but have not specified the set of persistent classes. OpenJPA must look for Metadata for every loaded class,which might increase class load times significantly.
我认为javaagent的第二个参数是我指定了类,但我错了。
这是我的persistence.xml:
<persistence xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.2"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_2.xsd">
<!-- Define persistence unit -->
<persistence-unit name="post">
<class>main.java.entity.Post</class>
<properties>
<property name="openjpa.DynamicEnhancementAgent" value="true"/>
<property name="javax.persistence.jdbc.url" value="jdbc:MysqL://localhost:3306/DSTEST" />
<property name="javax.persistence.jdbc.driver" value="com.MysqL.jdbc.Driver" />
<property name="javax.persistence.jdbc.user" value="xxx" />
<property name="javax.persistence.jdbc.password" value="xxx" />
</properties>
</persistence-unit>
这是我的实体:
package main.java.entity;
import javax.persistence.Entity;
import javax.persistence.Id;
@Entity (name="post")
public class Post {
@Id
private Integer postid;
private String user;
private Integer datum;
private String inhalt;
public Integer getPostid() {
return postid;
}
public void setPostid(Integer postid) {
this.postid = postid;
}
public String getUser() {
return user;
}
public void setUser(String user) {
this.user = user;
}
public Integer getDatum() {
return datum;
}
public void setDatum(Integer datum) {
this.datum = datum;
}
public String getInhalt() {
return inhalt;
}
public void setInhalt(String inhalt) {
this.inhalt = inhalt;
}
}
我正在Ubuntu上使用Intellij。
解决方法
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