问题描述
在python中，当计算大量（整数或浮点数）时，该数字似乎将以科学计数法存储，因此会变得不准确。 例如
>>> rst = 15
>>> dst = [10,14,10,14]
>>> [float(dst[i])*float(rst)**float(i) for i in range(len(dst))]
[10.0,210.0,2250.0,47250.0,506250.0,10631250.0,113906250.0,2392031250.0,25628906250.0,538207031250.0,5766503906250.0,121096582031250.0,1297463378906250.0,2.724673095703125e+16]
>>> # please note the last element is stored in scientific notation
>>> # but if calculate 14*15**13 (same as how the last element is calculated)
>>> 14*15**13
>>> 27246730957031250
>>> # result is fine
>>> 14*15**13 == dst[-1]
>>> False
我应该如何在python大数计算中抑制科学计数法
解决方法
please note the last element is stored in scientific notation
but if calculate 14*15**13 (same as how the last element is calculated)
最后一个元素为float，而14**15**13的结果为int。如果仅使用int（而不划分），则会得到int，在这种情况下将不使用e表示法。
请注意数字在内存中的存储方式以及在计算中的使用方式（以浮点数或整数形式）与数字如何转换为字符串并在屏幕上显示（四舍五入为整数，定点或科学计数法）之间的区别。这是两个完全独立的概念，因此看到以某种方式显示的内容并不会自动说出准确性。
In [8]: i = 123
In [9]: print('integer displayed as int: %i,as fixed point: %.1f or %.3f,and in scientific notation: %e' % (i,i,i))
integer displayed as int: 123,as fixed point: 123.0 or 123.000,and in scientific notation: 1.230000e+02
In [10]: f = 1.23
In [11]: print('floating point displayed as int: %i,and in scientific notation: %e' % (f,f,f))
floating point displayed as int: 1,as fixed point: 1.2 or 1.230,and in scientific notation: 1.230000e+00