Couchbase查询按数组中的标签过滤

问题描述

我有一个作者桶。在这个存储桶中，我保留了作者信息和作者的文章。我想从作者存储桶中选择具有所需标签的文章。

我已经尝试过了，但是找不到过滤方法。

SELECT art.* FROM author AS a 
UNnesT a.articles AS art
WHERE art.tags = 'History'

这是作者存储桶：

{
  "about": {
    "name": "sassa","userName": "sassatur"
  },"articles": [
    {
      "authorId": [
        "8c7ba33e-0674-4d99-bfad-29d144028bc9"
      ],"claps": [],"comments": [],"content": {
        "articleType": "HTML","data": "My First Article"
      },"id": "71d6fa22-61be-4a93-8e86-8d569080da97","publishStatus": "UNLISTED","statistic": {
        "articleId": "71d6fa22-61be-4a93-8e86-8d569080da97","views": [
          1602683127039,1602683148270
        ]
      },"tags": [
        "Art,History"
      ],"title": "Culture"
    },{
      "authorId": [
        "8c7ba33e-0674-4d99-bfad-29d144028bc9"
      ],"id": "81d6fa22-63be-4a93-8e86-8d569080da97","statistic": {
        "views": [
          1602683127039,"tags": [
        "Art"
      ],"title": "Culture"
    }
  ],"id": "8c7ba33e-0674-4d99-bfad-29d144028bc9",}

解决方法

尝试使用ANY/IN/SATISFIES，如下所示：

SELECT art.* FROM author AS a 
UNNEST a.articles AS art
WHERE ANY x IN art.tags SATISFIES x == 'Art' END;

这在您的示例中适用于“艺术”，但不适用于“历史记录”，因为您存储标签的方式不同。它是一个数组，但似乎有一个带有逗号分隔值的单（？）项。因此，我建议使用"tags": ["Art,History"]代替"tags": ["Art","History"]，然后它将起作用。

但是，如果您使用逗号分隔的字符串，则可以同时使用SPLIT和ARRAY_CONTAINS：

SELECT art.* FROM author AS a 
UNNEST a.articles AS art
WHERE ANY x IN art.tags SATISFIES ARRAY_CONTAINS(SPLIT(x,","),'History') END;