mzcdf2peaks不接受由Matlab r2020a中的mzcdfread创建的给定数据

问题描述

所以我有以下代码和错误:

int* array = new int[variable][variable2]

这是一个简单的.cdf文件。我希望最终输出为:

Final result

但是您看到的>> data = mzcdfread('sample1.cdf'); Reading filename: sample1.cdf Number of dimensions: 11 Unlimited Dimension: 8 Number of variables: 12 Number of attributes: 10 Exploring global netCDF attributes: acd_ec_version -> 1.0 dataset_completeness -> C1 aia_template_revision -> 1.0 netcdf_revision -> 3.4 languages -> English injection_date_time_stamp -> 20120404170129+-0500 separation_experiment_type -> Liquid Chromatography source_file_reference -> L:\chromatogram\web\sample 1.xy detector_unit -> AU retention_unit -> seconds Exploring netCDF dimensions: Name Length Dim_ID _2_byte_string 2 1 _4_byte_string 4 2 _8_byte_string 8 3 _16_byte_string 16 4 _32_byte_string 32 5 _64_byte_string 64 6 _128_byte_string 128 7 _255_byte_string 255 8 acd_ec_count 0 9 error_number 1 10 point_number 17999 11 Reading netCDF variables: Name Type Dim_ID NumAtt error_log 2 6 10 0 detector_maximum_value 5 0 detector_minimum_value 5 0 actual_run_time_length 5 0 actual_sampling_interval 5 0 actual_delay_time 5 0 ordinate_values 5 11 1 uniform_sampling_flag -> Y peak_retention_time 5 0 peak_name 2 0 peak_amount 5 0 peak_area 5 0 peak_height 5 0 >> mzcdf2peaks(data) Error using mzcdf2peaks (line 27) Input structure MZCDFSTRUCT must be created by MZCDFREAD. 函数对我不起作用,并导致此错误:

mzcdf2peaks

下面是this的示例,其中他们使用以下命令:

Error using mzcdf2peaks (line 27)
Input structure MZCDFSTRUCT must be created by MZCDFREAD.

当我在Unichrom中打开mzcdf_struct = mzcdfread('results.cdf'); [peaks,time] = mzcdf2peaks(mzcdf_struct) figure hold on for i = 1:numel(peaks) t = repmat(time(i),size(peaks{i},1),1); plot3(t,peaks{i}(:,2),'color',colors(i,:)) end view(70,60) xlabel('Time') ylabel(mzcdf_struct.mass_axis_label) zlabel(mzcdf_struct.intensity_axis_label) 文件时,它会起作用。

working

您可以在此处访问cdf文件:https://files.fm/u/j7yjb23c

所以我的问题是如何使Matlab sample1.cdf函数在此数据集上工作? 还有其他方法可以达到所需的输出吗?

解决方法

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