问题描述
我有一个函数,可以将Kafka主题中的XML读取为String格式,然后将其转换为JSON对象。
示例XML:
<Example>
<Object>
<Member1><![CDATA[]]</Member1>
<Member2><![CDATA[someText]]</Member2>
</Object>
</Example>
然后我有POJO类,例如:(带有lombok getter / setter / toString和jackson注释导入)
@Getter
@Setter
@ToString
@JacksonXMLRootElement(localName = "Example")
public class TXML {
@JacksonXmlProperty(localName = "Object")
private someObject object;
}
@Getter
@Setter
@ToString
public class someObject {
@JacksonXmlProperty(localName = "Member1")
private String member1;
@JacksomXmlProperty(localName = "Member2")
private String member2;
}
然后我正在使用MappingJackson2XmlHttpMessageConverter获取对象映射器,并使用该映射器将XML字符串映射到Example类。
@Autowired ObjectMapper xmlMapper;
@Autowired
private MappingJackson2XmlHttpMessageConverter xmlConverter;
...
xmlMapper = xmlConverter.getobjectMapper();
Example example = xmlMapper.readValue(xmlString,Example.class);
这将导致示例类具有以下内容:
Example
-> object
-> member1 : ""
-> member2 : "someText"
我希望member1为null,而不是空字符串。我该怎么做?
解决方法
您需要实现自己的com.fasterxml.jackson.databind.util.Converter
,它将在反序列化之后但设置为所需格式之前转换您的值。
示例实现:
class CDATAConverter implements Converter<String,String> {
@Override
public String convert(String value) {
return (value == null || value.length() == 0) ? null : value;
}
@Override
public JavaType getInputType(TypeFactory typeFactory) {
return typeFactory.constructType(String.class);
}
@Override
public JavaType getOutputType(TypeFactory typeFactory) {
return typeFactory.constructType(String.class);
}
}
您需要指示Jackson
使用它:
@Getter
@Setter
@ToString
class SomeObject {
@JsonDeserialize(converter = CDATAConverter.class)
@JacksonXmlProperty(localName = "Member1")
private String member1;
@JsonDeserialize(converter = CDATAConverter.class)
@JacksonXmlProperty(localName = "Member2")
private String member2;
}