Beeline无法与python中的subprocess.run一起使用，永远卡住

问题描述

我正在尝试通过Python脚本通过beeline连接并运行hql脚本。我无法使用subprocess.run或subprocess.popen运行。我可以直接在命令提示符下运行它

beeline_connect=str('"jdbc:hive2://192.168.0.100:10000/servicediscoveryMode=zooKeeper;zooKeeperNamespace=hiveserver2;transportMode=http;httpPath=cliservice;principal=hive/[e-mail]"')
        
#passing params as a list
 
         param_list= ['beeline -u' + beeline_connection,'-hivevar','VAR1=val1','VAR2=val2','VAR3=val3','VAR4=val4','VAR5=val5','-f','/my/path/filename.hql']

command = subprocess.run(param_list,check=True,stdout=subprocess.PIPE)
                output = command.stdout
                status = str(output.decode('utf-8'))
                print(
                    '****Its Failed****,return code {1} with return count {2} :'.format(command.returncode,status))

                if command.returncode > 0:
                    print('Job Failed. Raising exception')
                    raise Exception('Job ' + job_name + ' Failed')

            else:
               ## do something else###

##### i还尝试了shell = True和False并删除stdout

它永远卡住了，我联系beeline命令的方式有什么问题吗？我尝试了以下串联的许多组合，但没有运气。任何帮助都是非常可观的。谢谢

param_list =['beeline','-u' + beeline_connection...]
param_list =['beeline','-u',beeline_connection....]
 

解决方法

更改下面的代码行对我有用

param_list= ['beeline','-u',beeline_connection,'-hivevar','VAR1=val1','VAR2=val2','VAR3=val3','VAR4=val4','VAR5=val5','-f','/my/path/filename.hql']