问题描述
我有两个桌子,花费和预订,我想完全参加。由于表的性质(并非所有预订都具有支出,并且并非所有支出都具有booking_id,有时还分配了错误的booking_id),我想在join子句中执行条件语句。
select bk.booking_id,bk.company_id,bk.event_id,bk.total_amount_booked,sp.spend
from
(select booking_id,company_id,event_id,booked_rate,total_amount_booked
from bookings) bk
full join
(select booking_id,normalized_spend,spend
from spend) sp
on (bk.booking_id = sp.booking_id and bk.booked_rate = sp.normalized_spend)
or (bk.company_id = sp.company_id and bk.event_id = sp.event_id);
基本上,如果booking_id匹配且标准化支出与booked_rate匹配,则以该条件加入。 如果没有,请加入company_id和event_id。
但是,执行此查询会返回
FULL JOIN is only supported with merge-joinable join conditions;
有更好的方法吗? 使用Redshift
解决方法
这有点痛苦,但是您可以模拟full
和两个left joins
和union all
的连接:
select bk.booking_id,bk.company_id,bk.event_id,bk.total_amount_booked,sp.spend
from bookings bk
left join spend sp
on (bk.booking_id = sp.booking_id and bk.booked_rate = sp.normalized_spend)
or (bk.company_id = sp.company_id and bk.event_id = sp.event_id)
union all
select bk.booking_id,sp.spend
from spend sp
left join bookings bk
on (bk.booking_id = sp.booking_id and bk.booked_rate = sp.normalized_spend)
or (bk.company_id = sp.company_id and bk.event_id = sp.event_id)
where bk.booking_id is null
,
也许使用CASE语句,例如
...ON CASE WHEN (bk.booking_id = sp.booking_id and bk.booked_rate = sp.normalized_spend)
THEN (bk.booking_id = sp.booking_id and bk.booked_rate = sp.normalized_spend)
WHEN (bk.company_id = sp.company_id and bk.event_id = sp.event_id)
THEN (bk.company_id = sp.company_id and bk.event_id = sp.event_id)
END