剪刀石头布计划

问题描述

我对这段代码感到沮丧。我们的目标是创建一个剪刀纸游戏，最好的3个。我试图做一个“ while”循环，但是我全都错了，最终把它报废了，回到非循环代码

如果有人能启发我如何使它循环播放，直到计算机或玩家获得3分，我将非常感激！非常感谢 抱歉，我需要澄清，它需要循环播放直到用户或计算机赢得3次胜利，因此他们重新进行战斗直到用户或计算机获得3次胜利

import java.util.Scanner;
import java.util.Random;
    
public class RockPaperScissors
{

public static void main(String[] args)
{
    Scanner key;
    Random randGen;
    char userChoice,computerChoice;
    int winner,compInt;

    int computerScore;
    int userScore;
    int scoreCounter;

    /***** INITIALIZATION SECTION *****/
    key = new Scanner(System.in);
    randGen = new Random();
    userChoice = ' ';
    computerChoice = ' ';
    //winner = -1;
    compInt = -1;
    computerScore = 0;
    userScore = 0;
    scoreCounter = 0;

    System.out.println("What is your name?");
    String name = key.nextLine();
    System.out.println(name + " play rock,paper,or scissors with me!!");

    /***** INPUT SECTION *****/
    System.out.println("Please enter R for rock,P for paper,or S for scissors:");
    userChoice = key.next().toUpperCase().charAt(0);

    //key.close();

    /***** PROCESSING SECTION *****/
    compInt=randGen.nextInt(3);
    if (compInt == 0)
    {
        computerChoice = 'R';
    }
    else if (compInt == 1)
    {
        computerChoice = 'P';
    }
    else if (compInt == 2)
    {
        computerChoice = 'S';
    }
    
    winner = RockPaperScissors.decideWinner(userChoice,computerChoice);

    /***** OUTPUT SECTION *****/
    System.out.printf("Player: %c%nComputer: %c%n",userChoice,computerChoice);

   switch (winner)
    {
        case 0:
            System.out.println("It's a tie!");
            System.out.println(name + ": " + userScore + ",Computer:" + computerScore );
            break;

        case 1:
            System.out.println("You won!");
            userScore++;
            System.out.println(name + ": " + userScore + ",Computer:" + computerScore );
            break;

        case 2:
            System.out.println("Computer won!");
            computerScore++;
            System.out.println(name + ": " + userScore + ",Computer:" + computerScore );
            break;

        default:
            System.out.println("Invalid choice,try again.");
            break;
    }
    //System.out.println("Thanks for playing!);
}

/***** STATIC METHODS *****/
/**Description: given two characters (R,P,or S) determines winner using rock
 * paper rules. Assume input is valid and error checking is done in main
 * programme. **/

public static int decideWinner(char p1,char p2)
{
    String combo;
    combo = String.format("%c%c",p1,p2);

    switch(combo)
    {
        case "RS":
        case "PR":
        case "SP":
            return 1;

        case "RP":
        case "PS":
        case "SR":
            return 2;

        case "RR":
        case "PP":
        case "SS":
            return 0;

    }
    return -1;
}

}
/***************************************************
 while(userScore == 3)
        {
            System.out.println("You won the game" +name+ "! Congratulations");
            scoreCounter++;
        }
        while(computerScore == 3)
        {
            System.out.println("Sorry " +name+ ",Computer won...");
            scoreCounter++;
        }
 **************************************************/

解决方法

尝试将代码拆分为每个都有各自任务的方法，这样您就可以更轻松地布局和控制程序的行为。例如。在用户输入的情况下，可以在无效输入的情况下递归地调用该方法。 对于while循环，我只是添加了一个计数器，该计数器在每局游戏结束后都会增加，直到3。

import java.util.Scanner;
import java.util.Random;
    
public class RockPaperScissors
{

    private static int totalGames = 0;

public static void main(String[] args)
{
    Scanner key;
    Random randGen;
    char userChoice,computerChoice;
    int winner;

    int computerScore;
    int userScore;

    /***** INITIALIZATION SECTION *****/
    key = new Scanner(System.in);
    randGen = new Random();
    computerChoice = ' ';
    //winner = -1;
    computerScore = 0;
    userScore = 0;

    System.out.println("What is your name?");
    String name = key.nextLine();
    System.out.println(name + " play rock,paper,or scissors with me!!");


    while(totalGames < 3) {
        userChoice = getUserChoice(key,false);

        /* PROCESSING SECTION */
        computerChoice = getComputerChoice(computerChoice,randGen.nextInt(3));

        winner = RockPaperScissors.decideWinner(userChoice,computerChoice);

        totalGames++;

        /* OUTPUT SECTION */
        System.out.printf("Player: %c%nComputer: %c%n",userChoice,computerChoice);

        switch (winner) {
            case 0:
                System.out.println("It's a tie!");
                System.out.println(name + ": " + userScore + ",Computer:" + computerScore);
                break;

            case 1:
                System.out.println("You won!");
                userScore++;
                System.out.println(name + ": " + userScore + ",Computer:" + computerScore);
                break;

            case 2:
                System.out.println("Computer won!");
                computerScore++;
                System.out.println(name + ": " + userScore + ",Computer:" + computerScore);
                break;

            default:
                System.out.println("Invalid choice,try again.");
                break;
        }
    }
    //System.out.println("Thanks for playing!);
}

    private static char getComputerChoice(char computerChoice,int compInt) {
        if (compInt == 0)
        {
            computerChoice = 'R';
        }
        else if (compInt == 1)
        {
            computerChoice = 'P';
        }
        else if (compInt == 2)
        {
            computerChoice = 'S';
        }
        return computerChoice;
    }

    private static char getUserChoice(Scanner key,boolean retry) {
        char userChoice;
        /* INPUT SECTION */
        if(retry)
            System.out.println("You entered an invalid input,please try again...");
        System.out.println("Please enter R for rock,P for paper,or S for scissors:");
        try {
            userChoice = key.next().toUpperCase().charAt(0);
            if(userChoice != 'R' && userChoice != 'P' && userChoice != 'S')
                return getUserChoice(key,true);
        } catch (Exception e){
            return getUserChoice(key,true);
        }
        return userChoice;
    }

/***** STATIC METHODS *****/
/**Description: given two characters (R,P,or S) determines winner using rock
 * paper rules. Assume input is valid and error checking is done in main
 * programme. **/

public static int decideWinner(char p1,char p2)
{
    String combo;
    combo = String.format("%c%c",p1,p2);

    switch(combo)
    {
        case "RS":
        case "PR":
        case "SP":
            return 1;

        case "RP":
        case "PS":
        case "SR":
            return 2;

        case "RR":
        case "PP":
        case "SS":
            return 0;

    }
    return -1;
}

}
/***************************************************
 while(userScore == 3)
        {
            System.out.println("You won the game" +name+ "! Congratulations");
            scoreCounter++;
        }
        while(computerScore == 3)
        {
            System.out.println("Sorry " +name+ ",Computer won...");
            scoreCounter++;
        }
 **************************************************/